Question

我试图制作文件名递增的单个文件的726份副本，即00001_2.jpg，00002_2.jpg等：

for /l %%A in (1,1,726) do (
    set /a i+=1

    rem Add leading zeroes:
    set FileName=00000!%%A!_2
    rem Trim to only four digits, from the end
    set FileName=!FileName:~-5!
    rem Add "output_" and extension again
    set FileName=!FileName!%%~xf
    rem Rename the file
    copy "2-original.jpg" "!FileName!"

)

这只是一遍又一遍地生成一个名为!FileName!的文件。我做错了什么？

Answer 1

感谢Squashman，这很有用

SETLOCAL ENABLEDELAYEDEXPANSION

for /l %%A in (1,1,726) do (
set /a i+=1

rem Add leading zeroes:
set FileName=000000%%A_2
rem Trim to only four digits, from the end
set FileName=!FileName:~-7!
rem Add "output_" and extension again
set FileName=!FileName!.jpg
rem Rename the file
copy "2-original.jpg" "!FileName!"

)

Windows Batch制作文件的多个副本

1 个答案: