Question

我有一个看起来像这样的字典：

BACKPACK = {'granola bar': 1, 'cooked meat': 1, 'raw meat': 1, 'dried foods': 1}

我想要做的是检查列表中是否有一个或多个元素出现在该字典中，如果是，我想转到下一个方法，如果不是，我想做其他的事情。

BACKPACK = {'granola bar': 1, 'cooked meat': 1, 'raw meat': 1, 'dried foods': 1}
HEALTH = 25

def rest():
    print formatter()

    foods = ['granola bars', 'cooked meat', 'dried foods']

    for food in foods:
        if food in BACKPACK:
            eat_food(BACKPACK, HEALTH)
            break
        else:
            print "You don't have any food in your pack." \
                  " You decide to go hunting."
        #  go_hunting()

def eat_food(food, health):
    print food
    print health

如果dict中的键与功能中的列表一致，我想要打印出可供吃的食物列表。

例如，如果我有这个：

BACKPACK = {'cooked meat': 1, 'raw meat': 1}
foods = ['granola bars', 'cooked meat', 'dried foods', 'raw meat']

这应输出：

1. cooked meat
2. raw meat

我为这种困惑道歉

Answer 1

编辑：你的循环是错误的使用这个

BACKPACK ={'cooked meat': 1, 'raw meat': 1}
HEALTH = 25





def rest():
    # print formatter()

    foods = ['granola bars', 'cooked meat', 'dried foods', 'raw meat']

    for food in BACKPACK:
        if food in foods:
            eat_food(food,HEALTH)
        else:
            print "You don't have any food in your pack." \
                  " You decide to go hunting."
        #  go_hunting()

def eat_food(food,health):
    #get rid of food
    #add health
    print food



rest()

Answer 2

这你需要什么？它应该现在正常工作：

BACKPACK = {'raw meat': 1, 'raw meat': 1, 'granola bar': 1, 'dried foods': 1, 'cooked meat': 1}
HEALTH = 25

def rest():

    foods = ['granola bar', 'cooked meat', 'dried foods']

    back = {}

for x in foods:
    for y in BACKPACK:
        if y in foods:
            back[y] = 1

for key, value in back.items():
    print("1. " + str(key))


def eat_food(food, health):
    print(food)
    print(health)

rest()

Answer 3

如果您只想获取列表中的所有密钥，则应使用集：

intersection = set(mylist) & set(mydict.keys())

如果没有，交集将是一个带有假bool的空集，否则它将具有真正的bool。要检查是否有这样的元素，你可以写下：

if intersection:
    do_sth
else:
    do_sth_else

如何遍历dict以查看列表的出现是否与一个或多个键匹配？

3 个答案: