Question

我目前在基于netty的websocket服务器上工作。我试图实现一个登录功能，但我有一些问题。我初始化的管道如下：

pipeline.addLast(new HttpServerCodec());
pipeline.addLast(new HttpObjectAggregator(65536));
pipeline.addLast(new WebSocketServerCompressionHandler());
pipeline.addLast(new WebSocketServerProtocolHandler(WEBSOCKET_PATH, null, true));
pipeline.addLast(new RequestHandler(WEBSOCKET_PATH));
pipeline.addLast("HandlerLogin", new FrameHandlerLogin());

在成功登录之后，FrameHandlerLogin应该更改管道，我认为这些线路可以完成工作，但没有任何变化：

ctx.pipeline().addLast("HandlerSQL", new FrameHandlerSQL());
ctx.pipeline().remove("HandlerLogin");

是否存在错误或是否需要做一些额外的工作？

谢谢，Schere

确定如此详细：我主要使用netty提供的websocket示例。服务器以：

启动

erverBootstrap bootstrap = new ServerBootstrap();
        bootstrap.group(bossGroup, workerGroup).channel(NioServerSocketChannel.class)
                .handler(new LoggingHandler(LogLevel.INFO))
                .childHandler(new PipelineInitializer(sslCtx));

        Channel ch = bootstrap.bind("localhost",PORT).sync().channel();

        System.out.println("Open your web browser and navigate to " + "https" + "://127.0.0.1:" + PORT + '/');

        ch.closeFuture().sync();

PipelineInitializer初始化了上面列出的所有处理程序。 Runnig应用程序和通过Firefox连接是没有问题的。输入用户名和密码也有效。 FramHandlerLogin执行以下操作：

protected void channelRead0(ChannelHandlerContext ctx, WebSocketFrame frame) throws Exception {
    String recievedUser;
    String recievedPsw;

    if (frame instanceof TextWebSocketFrame) {
        String request = ((TextWebSocketFrame) frame).text();
        JSONObject in = (JSONObject) JSONValue.parse(request);
        recievedUser = (String) in.get("user");
        recievedPsw = (String) in.get("psw");
        if (recievedUser.equals(USER) && recievedPsw.equals(PASSWORD)) {
            System.out.println("Recieved correct User and Password!");


            ctx.pipeline().addLast("HandlerSQL", new FrameHandlerSQL());
            ctx.pipeline().remove("HandlerLogin");

            ctx.channel().writeAndFlush(new TextWebSocketFrame("Success"));


        } else {
//some error handling

到目前为止一切顺利。 websocket请求/sql.html，如果他收到＆＃34;成功＆＃34;

RequestHandler现在将uri和管道记录到控制台。

protected void channelRead0(ChannelHandlerContext ctx, FullHttpRequest req) throws Exception {
    // Handle a bad request.
    ...

    // Allow only GET methods.
    ...

//TODO Debug remove
//after a successfull client login, the requested uri should be sql.html
//also the pipeline should use the FrameHandlerSQL and not the FrameHandlerLogin. 
//The problem is, that the FrameHAndlerLogin is still active and the FrameHandlerSql is not
    System.out.println("URI:" + req.uri() );
    if(ctx.pipeline().get("HandlerLogin") != null){
        System.out.println("Piepline: Login" );
    } else if(ctx.pipeline().get("HandlerSQL") != null) {
        System.out.println("Piepline: SQL");
    }
    // Send the index page
    if ("/".equals(req.uri()) || "/index.html".equals(req.uri())) {
        String webSocketLocation = getWebSocketLocation(ctx.pipeline(), req, websocketPath);
        ByteBuf content = null;
        content = PageLoaderLogin.getContent(webSocketLocation);
        FullHttpResponse res = new DefaultFullHttpResponse(HTTP_1_1, OK, content);
        res.headers().set(HttpHeaderNames.CONTENT_TYPE, "text/html; charset=UTF-8");
        HttpUtil.setContentLength(res, content.readableBytes());
        sendHttpResponse(ctx, req, res);

} else if ("/sql.html".equals(req.uri())) {
        String webSocketLocation = getWebSocketLocation(ctx.pipeline(), req, websocketPath);
        ByteBuf content = null;
        content = PageLoaderSQL.getContent(webSocketLocation);
        FullHttpResponse res = new DefaultFullHttpResponse(HTTP_1_1, OK, content);
        res.headers().set(HttpHeaderNames.CONTENT_TYPE, "text/html; charset=UTF-8");
        HttpUtil.setContentLength(res, content.readableBytes());
        sendHttpResponse(ctx, req, res);
    } else {
        sendHttpResponse(ctx, req, new DefaultFullHttpResponse(HTTP_1_1, NOT_FOUND));
    }
}

它表示登录成功，但下一个请求的piepline仍然是旧的，如您在RequestHandler附近的评论中所见。

所有请求的上下文是否相同？或者是为每个请求创建的新上下文？我想这可能是问题？

Schere

Netty 4.1.2动态管道变更

0 个答案: