我正在制作一个每隔一段时间刷新一次数据的函数,而且我遇到了我的请求链问题。问题是我有一个for循环运行异步请求,for循环将在请求完成之前完成。
setInterval(function(){ // this updates the total hours of all members every 10 seconds
request({ // this gets all of the loyalty program members
url: "",//omitted
method: "GET"
},
function(listError, listResponse, listBody) {
if(listError == null && listResponse.statusCode == 200) {
var varBody = {};
var listObj = JSON.parse(listBody);
for(var i = 0; i < listObj.result.length; i++) { // parses through all of the members to update their hours
console.log(i);//****PRINT STATEMENT
varBody.index = i;
varBody.memberID = listObj.result[i].program_member.id;
request({ //we do this request to get the steam ID of the program member
url: "",//omitted
method: "GET"
},
function(fanError, fanResponse, fanBody) {
var fan = JSON.parse(fanBody);
if(fanError == null && fanResponse.statusCode == 200 && fan.result.profiles.length != 0) { // make sure that the profile isn't empty
request({
url:"",//omitted
method: "GET"
},
function(hourError, hourResponse, hourBody) {
if (hourError == null && hourResponse.statusCode == 200) {
var gameList = JSON.parse(hourBody);
var minutes = 0;
for (var j = 0; j < gameList.response.games.length; j++) { // for loop to calculate the minutes each user has on steam
minutes += gameList.response.games[j].playtime_forever;
}
var deltaHours = 1;
if(deltaHours != 0) {
var transaction = { // updated member object to be inserted
pointsearned: deltaHours,
pointsused: 0,
loyaltyprogram_id: loyaltyID,
programmember_id: memberID
};
request({ // POST request to update the member
url: "",//omitted
method: "POST",
body: JSON.stringify(transaction),
headers: {
"Content-Type": "application/json"
}
},
function(updateError, updateRes, updateBody) {
if(updateError == null && updateRes.statusCode == 200) {
console.log("Success");//****PRINT STATEMENT
}
}
);
}
}
}
);
}
}
);
}
}
console.log("Users Updated"); //****PRINT STATEMENT
}
);
}, 10000);
如果我要运行此代码,则会打印:
0
1
2
3
Success
Success
Success
Success
我知道问题是什么。事实上,for-loop并没有等待请求完成。我不知道的是解决这个问题的方法。有没有人有任何想法?
答案 0 :(得分:10)
为了完整性,顺序执行异步事务的方式&#34;手工&#34;是使用递归:
function dothings(things, ondone){
function go(i){
if (i >= things.length) {
ondone();
} else {
dothing(things[i], function(result){
return go(i+1);
});
}
}
go(0);
}
答案 1 :(得分:5)
您需要async库。
例如,
library(dplyr)
library(ggmap)
library(rgdal)
library(broom)
# Read in shapefile, project into long-lat
# Create 'tbox' which is a minimum bounding box around the shapefile
tracts <- readOGR(dsn = ".", layer = "CensusTracts2010") %>%
spTransform("+proj=longlat +ellps=WGS84")
tbox <- bbox(tracts)
# Plot data
tract_plot <- tidy(tracts)
DetroitMap <- qmap("Detroit", zoom = 11)
DetroitMap + geom_polygon(data = tract_plot, aes(x = long, y = lat, group = id), color = "black", fill = NA) +
coord_cartesian(xlim = c(tbox[1,1], tbox[1,2]),
ylim = c(tbox[2,1], tbox[2,2]))
可以这样写:
for(var i = 0; i < listObj.result.length; i++) {
varBody.index = i;
varBody.memberID = listObj.result[i].program_member.id;
request(
...
, function () {
// Do more Stuff
});
}
在异步中有很多方便的实用程序函数,这使得回调变得更加容易。