如果我有以下JSON对象:
taxcodes = {
"CA_MONO CO": {
"Rate": 1,
"Country": "United States"
}
}
使用taxcodes["CA_MONO CO"].Rate
可以完美地检索1
。
现在我的问题是,如果我有一个变量,请说:x = "CA_MONO CO_MAMMOTH LAKES"
。
taxcodes[x].Rate
, _MAMMOTH LAKES
显然无效。
所以我所做的就是在CO_
之后删除所有字符串,这会给我CA_MONO
然后将' CO'
重新添加到字符串的末尾,这会给我CA_MONO CO
。
var modifiedx = x.substring(0, x.indexOf('CO_')) + ' CO';
然后我尝试使用taxcodes[modifiedx].Rate
来提取数据,而{{1}}没有提取数据。
答案 0 :(得分:1)
附加
.bar .button.button-clear .icon:before{
font-size: 12px;
}

答案 1 :(得分:0)
那是因为你有SyntaxError: missing ; before statement @(shell)
的额外空间。因此值为$ mongo
MongoDB shell version: 3.2.8
connecting to: test
Welcome to the MongoDB shell.
For interactive help, type "help".
For more comprehensive documentation, see
http://docs.mongodb.org/
Questions? Try the support group
http://groups.google.com/group/mongodb-user
Server has startup warnings:
2016-08-04T11:58:21.138-0400 I CONTROL [initandlisten]
2016-08-04T11:58:21.138-0400 I CONTROL [initandlisten] ** WARNING: /sys/kernel/mm/transparent_hugepage/enabled is 'always'.
2016-08-04T11:58:21.138-0400 I CONTROL [initandlisten] ** We suggest setting it to 'never'
2016-08-04T11:58:21.138-0400 I CONTROL [initandlisten]
2016-08-04T11:58:21.139-0400 I CONTROL [initandlisten] ** WARNING: /sys/kernel/mm/transparent_hugepage/defrag is 'always'.
2016-08-04T11:58:21.139-0400 I CONTROL [initandlisten] ** We suggest setting it to 'never'
2016-08-04T11:58:21.139-0400 I CONTROL [initandlisten]
> show dbs
mydb 0.000GB
local 0.000GB
> use mydb
switched to db mydb
> show collections
201607012
> db
mydb
> mydb.201607012.find()
2016-08-04T12:10:23.826-0400 E QUERY [thread1] SyntaxError: missing ; before statement @(shell):1:4
> db.201607012.find()
2016-08-04T12:10:29.000-0400 E QUERY [thread1] SyntaxError: missing ; before statement @(shell):1:2
> db.201607012.find()
2016-08-04T12:11:09.115-0400 E QUERY [thread1] SyntaxError: missing ; before statement @(shell):1:2
> db.201607012.stats()
2016-08-04T12:13:06.022-0400 E QUERY [thread1] SyntaxError: missing ; before statement @(shell):1:2
而不是' CO'
。只需删除它:
"CA_MONO CO"
答案 2 :(得分:0)
var modifiedx = x.substring(0, x.indexOf('CO_')) + ' CO';
应该是
var modifiedx = x.substring(0, x.indexOf('CO_')) + 'CO';