Question

这里是通知方法

public function activetask() {
              $notification['ReceiverID']=$this->input->post('user_reciver_id');
              $notification['SenderID']=$this->input->post('createdby');
              $notification['Status']=$this->input->post('task');
              $notification['AppID']=$this->input->post('App_id'); 
              $notification['TaskID']=$this->input->post('PhaseID');
              $notification['CreatedDate']=date('D M Y h:i');
              $this->Mapps->notification($notification);

            if($this->input->post('user_reciver_id')==$this->session->userdata('id')){

echo '<audio controls autoplay>
  <source src="<?php echo base_url(); ?>notify.ogg" type="audio/ogg">
  <source src="<?php echo base_url(); ?>notify.mp3" type="audio/mpeg">
Your browser does not support the audio element.
</audio>';
             }

此处点击事件的ajax函数调用

function active(task,user_reciver_id,createdby,Task_id,App_id,PhaseID){
     $.ajax({
      type: "post",
      url:  '<?php echo base_url();?>users/activetask',
      cache: false,       
      data: {task: task,Task_id:Task_id,App_id:App_id,PhaseID:PhaseID,user_reciver_id:user_reciver_id,createdby:createdby},
      success: function(response){ 
          location.reload();
      }
   });
  }

它不适合我在哪里出问题如何解决它

我将一个用户的一些细节发送给其他人如果接收者用户登录，则听取通知声音

Answer 1

您需要将回应响应附加到某个元素。

首先，在html中创建一个元素。

<div id="audios" style="display:none;">We are audios!</div>

然后，在ajax中获取响应并在重新加载窗口之前将其附加到#audios。

     $.ajax({
          type: "post",
          url:  '<?php echo base_url();?>users/activetask',
          cache: false,       
          data: {task: task,Task_id:Task_id,App_id:App_id,PhaseID:PhaseID,user_reciver_id:user_reciver_id,createdby:createdby},
          success: function(response){ 
              var audio_html = response;
              $('#audios').append(audio_html);
              location.reload();
          }
      });

codeigniter声音通知系统

1 个答案: