import java.io.*;
import java.util.*;
class StepfordHouses {
private ArrayList<Integer> houses; // A list containing houses
private TreeSet<Integer> ordered; // An ordered treeset of houses
private TreeSet<Integer> processed; // Elements already processed
private String inpline[]; // An array of String holing houses heights in physical order
private int disorientedindex; // The index for the Street
private int size; // Number of houses in the Street
public StepfordHouses() // Constructor for init
{
houses = new ArrayList<Integer>();
ordered = new TreeSet<Integer>();
processed = new TreeSet<Integer>();
// Basic Input from Text-File (Codechef Requirment)
try {
BufferedReader br = new BufferedReader(new InputStreamReader(
System.in));
size = Integer.parseInt(br.readLine());
inpline = br.readLine().split(" ");
} catch (IOException e) {
System.out.println("BAAAAAAAAAM!!");
}
for (int c = 0; c < size; c++) // Populating Houses
{
Integer tmp = Integer.parseInt(inpline[c]);
houses.add(tmp);
ordered.add(tmp);
}
}
public int calcIndex()
{
int c = 0;
while (c < size) {
Iterator<Integer> it = ordered.iterator();
Integer h1 = houses.get(c); // Get an element from the raw ArrayList of Houses
Integer h = it.next(); // Get an element from the Iterator
while (h1.equals(h) != true) {
if (processed.contains(h1) == false) { // The element is not already processed
System.out.println(h1 + " " + h);
disorientedindex++;
}
h = it.next(); // Get an element from the Iterator
}
processed.add(h1);
c++;
it = null;
}
return disorientedindex;
}
}
public class Work {
public static void main(String args[]) {
StepfordHouses sh = new StepfordHouses();
System.out.println(sh.calcIndex());
}
}
contains()方法不像我期望的那样工作,即比较整数!
输出为15,当时为9
if(processed.contains(h1)==false)
正常工作,当元素已经存在时返回true!
代码哪里错了?
答案 0 :(得分:0)
逻辑是有缺陷的。 processed.add(h1);
被称为N次,但processed.contains(h1)
被称为N * N次。因此,根据输入,您可以使用迷失方向索引&lt;&gt; Ñ