Question

Hello Stack Overflow社区！

我的MySQL查询有点问题。我之后的是一个查询，它将从表中返回所有Project_Cost的总和，但我希望它在每个时间帧中将其拆分为不同的部分。对我而言，我希望它们每个月分开（例如：六月，七月，八月等所有费用）

我现在设置的方式是它以一个月的增量分割它们，但这是由当前日期确定的。所以基本上这只会在本月的第一天起作用，从那时起它就不准确了。

有人可以帮我编辑这个查询，以便它能告诉我我之后的内容吗？我已经测试了很多我已经看过的方法，但没有什么能给我提供我所追求的东西。

SELECT SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -1 MONTH)) AND NOW(),Project_Cost,0)) AS A,
    SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -2 MONTH)) AND DATE(DATE_ADD(NOW(), INTERVAL -1 MONTH)),Project_Cost,0)) AS B,
    SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -3 MONTH)) AND DATE(DATE_ADD(NOW(), INTERVAL -2 MONTH)),Project_Cost,0)) AS C,
    SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -4 MONTH)) AND DATE(DATE_ADD(NOW(), INTERVAL -3 MONTH)),Project_Cost,0)) AS D,
    SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -5 MONTH)) AND DATE(DATE_ADD(NOW(), INTERVAL -4 MONTH)),Project_Cost,0)) AS E,
    SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -6 MONTH)) AND DATE(DATE_ADD(NOW(), INTERVAL -5 MONTH)),Project_Cost,0)) AS F,
    SUM(IF(DateSigned BETWEEN DATE(DATE_ADD(NOW(), INTERVAL -7 MONTH)) AND DATE(DATE_ADD(NOW(), INTERVAL -6 MONTH)),Project_Cost,0)) AS G
    FROM project
    WHERE program = '1';

Answer 1

您可以使用YEAR(date)*12+MONTH(date)来比较月份：

SELECT SUM(IF(YEAR(DateSigned)*12+MONTH(DateSigned) = YEAR(Now())*12+MONTH(Now()),Project_Cost,0)) AS CurrentMonth,
       SUM(IF(YEAR(DateSigned)*12+MONTH(DateSigned) = YEAR(Now())*12+MONTH(Now())-1,Project_Cost,0)) AS PreviousMonth,
       SUM(IF(YEAR(DateSigned)*12+MONTH(DateSigned) = YEAR(Now())*12+MONTH(Now())-2,Project_Cost,0)) AS C
       /* etc... */
FROM   project
WHERE  program = '1'

Answer 2

可能我不明白你的问题，但看起来是一个小组（年和月）

SELECT year(DateSigned), month(DateSigned), sum(Project_Cost)
from project 
WHERE program = '1'
Group By year(DateSigned), month(DateSigned)

MySQL查询 - 间隔求和

2 个答案: