我有一个应该更改滑块(角度光滑)的下拉菜单。选择菜单显示选项,当选择时幻灯片不更新。我使用的是角1.3.0。
我相信我已将其缩小到不更新价值的模型。
这是我的HTML:
<select class="form-control" ng-options="d.id as d.category for d in draggableObjects | object2Array | orderBy:'id'" ng-change="updateSlide()" ng-model="selectedSlideId"></select>
<slick class="slider" objs="obj" data="draggableObjects" settings="slickConfig" ng-if="slideLoaded">
<li ng-repeat="obj in draggableObject.item" class="draggable-item slide">
<div ng-drag="true" ng-drag-data="obj" data-allow-transform="true">
<img ng-src="{{obj.src}}" alt="{{obj.name}}">
{{obj.name}}
</div>
</li>
</slick>
这是应该更新到模型以触发ng-change的init和函数:
// selection from the select dropdown
$scope.$watch('selectedSlideId', function(newVal, oldVal) {
if (newVal !== oldVal) {
$scope.draggableObject = $scope.draggableObjects[newVal];
console.log('finally!');
} else {
$scope.draggableObject = $scope.draggableObjects[1];
console.log('id not updated');
}
});
// init dashboard
$scope.selectedSlideId = '1';
这是通过以下方式排序的json对象:
// draggable objects
$scope.draggableObjects = {
1: {
id: '1',
category: 'Slider',
item: [
{name:'slider one', src: 'images/placeholderslider.png'},
{name:'slider two', src: 'images/placeholderslider2.png'},
{name:'slider three', src: 'images/placeholderslider3.png'},
{name:'slider four', src: 'images/placeholderslider4.png'},
{name:'slider five', src: 'images/placeholderslider5.png'}
]
},
2: {
id: '2',
category: 'News',
item: [
{name:'news one', src: 'images/placeholdernews.png'},
{name:'news two', src: 'images/placeholdernews2.png'},
{name:'news three', src: 'images/placeholdernews3.png'},
{name:'news four', src: 'images/placeholdernews4.png'},
{name:'news five', src: 'images/placeholdernews5.png'}
]
}
};
Angular slick似乎正在使用ng-if和timeout更新:
// init and reInit slick
$scope.slideLoaded = true;
$scope.updateSlide = function() {
$scope.slideLoaded = false;
console.log('slide update');
$timeout(function() {
$scope.slideLoaded = true;
});
};
在控制台中我没有更新&#34; ID未被更新&#34; (来自选择初始化),&#34;幻灯片更新&#34;当从下拉列表中做出选择时,我也应该看到&#34;终于!&#34;从模型中更改选定的值。
感谢任何帮助。
答案 0 :(得分:0)
我在使用$scope.$watch('modelname' ,..
时也遇到过这个问题。我目前使用此功能 -
$scope.$watch(
function(){ return $scope.modelname;}, function(newVal, oldVal){
.......
}
)
撰写function
以返回model
代替modelname
(字符串)。这绝不会失败。