如何查找数组中的元素是否是字符串的子字符串？

Question

给定一个字符串s = "Leonhard Euler"，我需要找到我的姓氏数组中的元素是否是s的子字符串。例如：

s = "Leonhard Euler"
surnames = ["Cantor", "Euler", "Fermat", "Gauss", "Newton", "Pascal"]
if any(surnames) in s:
    print("We've got a famous mathematician!")

Answer 1

考虑if any(i in surnames for i in s.split()):。

这适用于s = "Leonhard Euler"和s = "Euler Leonhard"。

Answer 2

在将字符串拆分为列表后，您可以使用集合的isdisjoint属性来检查转换为集合的两个列表是否具有任何共同的元素。

s = "Leonhard Euler"
surnames = ["Cantor", "Euler", "Fermat", "Gauss", "Newton", "Pascal"]

strlist = s.split()
if not set(strlist).isdisjoint(surnames):
    print("We've got a famous mathematician!")

Answer 3

s = "Leonhard Euler"
surnames = ["Cantor", "Euler", "Fermat", "Gauss", "Newton", "Pascal"]

for surname in surnames:
   if(surname in s):
       print("We've got a famous mathematician!")

遍历姓氏中的每个字符串并检查其是否为s

的子字符串

Answer 4

如果你不需要知道s中的姓氏，你可以使用任何和列表理解来做到这一点：

if any(surname in s for surname in surnames):
    print("We've got a famous mathematician!")

Answer 5

实际上我没有测试代码，但应该是这样的（如果我理解了这个问题）：

var con = ConfigurationManager.ConnectionStrings["Oracle"].ConnectionString;