Question

这个目的是创建一个搜索条件，最终处理输出以显示基于匹配增加顺序的结果

“如果和foreach条件[关闭]中的PHP内爆函数”是一个不同的问题！

为什么以下代码失败？

$terms = array("HELLO", "HI", "HOWDY");
$row = array("HELLO", "HI", "Hey");
$chkcond = "in_array('".implode("',$"."row".")"." && in_array"."('",$terms)."',$"."row)";

echo "$chkcond<br/><br/>";

if ($chkcond) {
    echo "All Found in Array !<br>";}else{echo "Not Found !<br/>";
}

回声结果是

in_array('HELLO',$row) && in_array('HI',$row) && in_array('HOWDY',$row)

if条件输出"All Found in Array !"

当if条件表明所有三个字词都必须在行数组中为“All Found in Array”时，为什么在“True”时它会返回Howdy “行数组中不存在？

Answer 1

juste使用array_diff http://php.net/array_diff

<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");

$diff = array_diff($terms, $row);

if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}


$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey","HOWDY");

$diff = array_diff($terms, $row);

if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}

Answer 2

您可以使用array_diff

类似的东西：

<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$chkcond=array_diff($terms, $row);

var_dump($chkcond);

if(empty($chkcond)) {
    echo "All Found in Array !<br>";
} else {
    echo "Not Found !<br>";
}
?>

Answer 3

不确定你在尝试什么，但你可以使用array_diff。

admin_passwords

https://secure.php.net/manual/en/function.array-diff.php

Answer 4

如果您想坚持使用in_array，则需要循环使用条款：

<?php
    $terms=array("HELLO","HI","HOWDY");
    $row=array("HELLO","HI","Hey");

    $chkcond = true;
    foreach($row as $needle){
        if(!in_array($needle, $terms)){
            $chkcond = false;
            break;         
        }
    }

    if($chkcond){
        echo "All Found in Array !<br>";
    } else {
        echo "Not Found !<br>";
    }
?>

哎呀重新阅读你甚至不需要循环的手册http://php.net/manual/en/function.in-array.php：

<?php
    $terms=array("HELLO","HI","HOWDY");
    $row=array("HELLO","HI","Hey");
    if(in_array($row, $terms)){
        echo "All Found in Array !<br>";
    } else {
        echo "Not Found !<br>";
    }

?>

在if语句中使用implode时in_array失败

4 个答案: