Question

我的IntelXDK HTML5移动应用表单向MySQL数据库提交空值。

我的HTML（单个文件应用）

<label class="item item-input widget uib_w_6 d-margins" data-uib="ionic/input" data-ver="0" id="fullname">
    <input type="text" placeholder="Fullname" name="fullname">
</label>
<label class="item item-input widget uib_w_7 d-margins" data-uib="ionic/input" data-ver="0" id="email">
    <input type="email" placeholder="Email" name="email">
</label>
<label class="item item-input widget uib_w_8 d-margins" data-uib="ionic/input" data-ver="0" id="pass">
    <input type="password" placeholder="Password" name="pass">
</label>
<button class="button widget uib_w_9 d-margins button-positive" data-uib="ionic/button" data-ver="0" id="signup">
    Create Account
</button>
<span class="uib_shim"></span>

我的JS

$(document).on("click", "#signup", function (evt) {
    /* your code goes here */ 
    //these two lines take the values from inputs using jquery
    var input1 = $("#fullname").val();
    var input2 = $("#email").val();
    var input3 = $("#pass").val();

    //jquery ajax to send values to php using POST
    $.ajax({
        type: 'POST',
        url: 'http://localhost/signup.php',
        data: {
            fullname: input1,
            email: input2,
            pass: input3
        },
        success: function (response) {
            //from php using echo
            alert(response);
        }
    }); 

    return false;
});

和PHP文件

<?php
// Create connection
$conn = new mysqli("localhost", "user", "pass", "dbname");
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

$fullname = Trim(stripslashes($_POST['fullname'])); 
$email = Trim(stripslashes($_POST['email'])); 
$pass = Trim(stripslashes($_POST['pass'])); 

$sql = "INSERT INTO login (fullname, email, pass) VALUES ('$fullname','$email', '$pass')";

if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>

提交此表单后，它将在MySQL中创建空记录。

任何帮助表示感谢。

Answer 1

这是因为

<input type="text" placeholder="Fullname" name="fullname">

没有像id =＆＃34; fullname＆＃34;可用，你指的是它。

Jquery表单向Mysql提交空值

1 个答案: