Question

所以我正在创建这个网络应用程序，我需要从多个社交网络网站获取数据，并根据帖子创建日期和时间对它们进行排序，我需要将所有提要合并到一个数组中，然后再显示它们。

所以这是我到目前为止所做的：

- ＆gt;从twitter，facebook，Instagram获取数据

- ＆gt;包含所有数据的3个不同数组。

现在我需要想办法对它们进行排序并将它们合并到一个数组中....

写了这个函数，但需要时间：

function sortNjoin($arr1, $arr2)
{
    $length = count($arr1);
    $sortedArray = array();
    if(count($arr1)>count($arr2))
    {
        $length = count($arr2);
    }

    $date1 ='';
    $date2 = '';
    for($i=0;$i<$length;$i++)
    {
        for($j=0;$j<$length;$j++)
        {
            switch($arr1['type'])
            {
                case 'f':
                    $date1 = date_parse($arr1['dataInfo'][$i]['updated_time']);
                    break;
                case 't':
                    $date1 = date_parse($arr1['dataInfo'][$i]['created_at']);
                    break;
                case 'i':
                    $date1 = date_parse($arr1['dataInfo'][$i]['external_created_at']);
                    break;
            }
            switch($arr2['type'])
            {
                case 'f':
                    $date2 = date_parse($arr2['dataInfo'][$j]['updated_time']);
                    break;
                case 't':
                    $date2 = date_parse($arr2['dataInfo'][$j]['created_at']);
                    break;
                case 'i':
                    $date2 = date_parse($arr2['dataInfo'][$j]['external_created_at']);
                    break;
            }
            $date_string1 = date('Y-m-d H:i:s', mktime($date1['hour'], $date1['minute'], $date1['second'], $date1['month'], $date1['day'], $date1['year']));
            $date_string2 = date('Y-m-d H:i:s', mktime($date2['hour'], $date2['minute'], $date2['second'], $date2['month'], $date2['day'], $date2['year']));

            if($date_string1 >= $date_string2)
            {
                $sortedArray[$i]['dataInfo'] = $arr1['dataInfo'][$i];
                $sortedArray[$i]['type'] = $arr1['type'];
            }
            else
            {
                $sortedArray[$i]['dataInfo'] = $arr2['dataInfo'][$j];
                $sortedArray[$i]['type'] = $arr2['type'];
            }
        }
    }

    return $sortedArray;

}

Answer 1

看看usort。这允许您使用用户定义的函数对数组进行排序。

Answer 2

<强> UDPATE 注意：我有用户Facebook＆amp; Twitter数据

按值按降序排序的功能

function sortArr($a, $b){
    return $b['date'] - $a['date'];
}

代码

<?php
    //json to associative array
    $fb = json_decode(@'{"data": [{
                                 "id": "X999_Y999",
                                 "from": {
                                         "name": "Tom Brady", "id": "X12"
                                         },
                                  "message": "Looking forward to 2010!",
                                  "created_time": "2010-08-02T21:27:44+0000",
                                   "updated_time": "2010-08-02T21:27:44+0000"
                               }]}',true);
//twitter json

   $twitter = json_decode(@'{"results":[{
                                        "text":"@twitterapi  tinyurl.com/ctrefg",
                                         "from_user":"jkoum",
                                         "id":1478555574,
                                         "from_user_id":1833773,
                                         "created_at":"Wed, 08 Apr 2009 19:22:10 +0000"}]

                                        }',true);

//Rename Array's key to common key name
     $fb = array_map(function($fb) {
           return array(
                'id' => $fb['id'],
                'from' => $fb['from'],
                'message' => $fb['message'],
                'date' => $fb['updated_time']
           );
        }, $fb);

     $twitter = array_map(function($twitter {
           return array(
                'id' => $twitter ['id'],
                'from' => $twitter ['from_user'],
                'message' => $twitter ['text'],
                'date' => $fbtwitter 'updated_time']
           );
        }, $twitter );
     //Now Both Array has same key i.e id,from,message,date and we can merged them
      $mergedArr=array_merge($fb,$twitter);

     //Now sort the merge array by value of ['date'] and we get the result
     usort($mergedArr,"sortArr") // sortArr = function we've written above.
     print_r($mergedArr);
 ?>

注意：我只从JSON中选择了少量数据来减少空间。

!!我希望这可以帮助你!!

Answer 3

<?php

$foo = array(
    array(
        'title' => 'Foo One',
        'date_info' => array(
            'created_at' => '2006-12-12 10:00:30'
        ) 
    ),
    array(
        'title' => 'Foo Two',
        'date_info' => array(
            'created_at' => '2006-12-12 10:23:00'
        ) 
    ),
    array(
        'title' => 'Foo Three',
        'date_info' => array(
            'created_at' => '2006-12-12 10:47:00'
        ) 
    )
);
$bar = array(
    array(
        'title' => 'Bar One',
        'date_info' => array(
            'created_at' => '2006-12-12 10:00:00'
        ) 
    ),
    array(
        'title' => 'Bar Two',
        'date_info' => array(
            'created_at' => '2006-12-12 10:13:00'
        ) 
    ),
    array(
        'title' => 'Bar Three',
        'date_info' => array(
            'created_at' => '2006-12-12 10:47:30'
        ) 
    )
);


$all = array_merge($foo, $bar);
usort($all,
    function($a, $b) {
        $ts_a = strtotime($a['date_info']['created_at']);
        $ts_b = strtotime($b['date_info']['created_at']);

        return $ts_a > $ts_b;
    }
);
var_export($all);

输出：

array (
  0 => 
  array (
    'title' => 'Bar One',
    'date_info' => 
    array (
      'created_at' => '2006-12-12 10:00:00',
    ),
  ),
  1 => 
  array (
    'title' => 'Foo One',
    'date_info' => 
    array (
      'created_at' => '2006-12-12 10:00:30',
    ),
  ),
  2 => 
  array (
    'title' => 'Bar Two',
    'date_info' => 
    array (
      'created_at' => '2006-12-12 10:13:00',
    ),
  ),
  3 => 
  array (
    'title' => 'Foo Two',
    'date_info' => 
    array (
      'created_at' => '2006-12-12 10:23:00',
    ),
  ),
  4 => 
  array (
    'title' => 'Foo Three',
    'date_info' => 
    array (
      'created_at' => '2006-12-12 10:47:00',
    ),
  ),
  5 => 
  array (
    'title' => 'Bar Three',
    'date_info' => 
    array (
      'created_at' => '2006-12-12 10:47:30',
    ),
  ),
)

比较多个数组并快速排序它们

3 个答案: