Question

我不知道为什么我的表格不起作用，这是我的代码：添加单词因为无法发布编辑.......................................... .... P.S 所有其他代码完美无缺!!!

页面：1：

<button id="Head" onclick="rollHead()">Head</button>
<button id="Tail" onclick="rollTail()">Tail</button>

<script>
function rollTail(){
    var die1 = document.getElementById("die1");
    var status = document.getElementById("status");
    var d1 = Math.floor(Math.random() * 2) + 1;
    if(d1 == 1)
    {
    die1.innerHTML = "You won!";
    fliped.innerHTML = "Fliped Tail!";
    var ajax = new XMLHttpRequest();
    ajax.open('POST','won.php',true);
    ajax.send();
    }
    else if (d1 == 2)
    {
    die1.innerHTML = "You lose!";
    fliped.innerHTML = "Fliped Head!";
    var ajax = new XMLHttpRequest();
    ajax.open('POST','lose.php',true);
    ajax.send();
    }
}
function rollHead(){
    var die1 = document.getElementById("die1");
    var status = document.getElementById("status");
    var d1 = Math.floor(Math.random() * 2) + 1;
    if(d1 == 1)
    {
    die1.innerHTML = "You lose!";
    fliped.innerHTML = "Fliped Tail!";
    var ajax = new XMLHttpRequest();
    ajax.open('POST','lose.php',true);
    ajax.send();
    }
    else if (d1 == 2)
    {
    //alert(document.getElementById('wonorlose').value );
    die1.innerHTML = "You won!";
    fliped.innerHTML = "Fliped Head!";
    var ajax = new XMLHttpRequest();
    ajax.open('POST','won.php',true);
    ajax.send();
    }
}
</script>

<form method="get" action="won.php">
<h2 align="center">
<input type="text" name="wonorlose" value=50>
</h2>
</form>

Page：won.php：

<?php
include_once 'dbconnect.php';
session_start();

if(!isset($_SESSION['user']))
{
 header("Location: /manopuslapis/index.php");
}
$res=mysql_query("SELECT * FROM users WHERE user_id=".$_SESSION['user']);
$userRow=mysql_fetch_array($res);

$wonorlose = $_GET["wonorlose"];
echo $wonorlose;
mysql_query("UPDATE `users` SET credits=credits+'$wonorlose' WHERE user_id=".$_SESSION['user']); 
?>

Answer 1

此行int[] array; var results = new List<Tuple<int[], int[]>>(); for (int i = 0; i < array.Length; i++) { var tuple = SplitIntArray(array, i); if (tuple.Item1.Sum() == tuple.Item2.Sum()) { results.Add(tuple); } } // results contains all pairs of arrays that sum to the same value. foreach (var tuple in results) { Console.WriteLine( String.Format("{0} == {1}", AggregateSumString(tuple.Item1), AggregateSumString(tuple.Item2))); }出现问题

won.php

你有$res=mysql_query("SELECT * FROM users WHERE user_id=".$_SESSION['user']);作为字符串..这必须是整数 OR 你必须添加引号：

$_SESSION['user']

或者在$res=mysql_query("SELECT * FROM users WHERE user_id='".$_SESSION['user']."'");之后添加$_SESSION["user"]，将(int)定义为整数。

<强>更新

teamviewer解决了问题。用户得到空白变量=，因为他在没有参数的情况下进行AJAX POST。我使用参数$wonorlose将AJAX POST更改为AJAX GET，现在它正常工作。最终代码只有作者。

表单方法无法正常工作

1 个答案: