Question

我的文件系统如下所示

Filesystem            Size  Used Avail Use% Mounted on
/dev/mapper/rootvg-rootvol
                       20G  3.7G   15G  20% /
tmpfs                  71G  8.0K   71G   1% /dev/shm

我的代码如下：

varone = df -h | awk ' {print $1 }'
vartwo = df -h | awk ' NR == 2 {print $2","$3","$4","$5","$6 }'
echo "$varone $vartwo" >> /home/jeevagan/test_scripts/sizes/excel.csv

我想将'df -h'导出到csv文件中。为什么我在一个变量中单独打印$1意味着“df -h”输出中有空格。我希望它以单行打印。

当我运行脚本时，它会抛出类似

的错误

varone: command not found

vartwo: command not found

Answer 1

你不能在等号周围放置空格，你需要反引用将命令的结果放在一个变量中。

试试这个：

extract($varianti);
var_dump($pa_colore);

Answer 2

如果您只是想捕获df -h

varOne=`df -h -P| awk '{print $1","$2","$3","$4","$5","$6 }'`
echo  "$varOne" >> /home/jeevagan/test_scripts/sizes/excel.csv

了解＆＃39; P＆＃39;这里

How can I *only* get the number of bytes available on a disk in bash?

echo命令在shell脚本中没有按预期工作

2 个答案: