我的桌子名为'bill',如下所示
Bill item totalprice
BILL_1 Fossil Watch 9000
BILL_1 Fastrack -
BILL_1 Fastrack -
BILL_2 Woodlands 7000
BILL_2 Woodlands -
BILL_3 Denim Shirt 9000
BILL_3 Levis Jean -
现在我需要结果如下面的结构
Bill item totalprice bill_count
BILL_1 Fossil Watch 9000 3
BILL_1 Fastrack - 3
BILL_1 Fastrack - 3
BILL_2 Woodlands 7000 2
BILL_2 Woodlands - 2
BILL_3 Denim Shirt 9000 2
BILL_3 Levis Jean - 2
我尝试使用以下查询,
SELECT bill,item,totalPrice,COUNT(bill) FROM bills GROUP BY bill;
但我没有按预期得到结果。
答案 0 :(得分:4)
SELECT b.bill, b.item, b.totalPrice, tmp.cnt
FROM bills b
JOIN
(
select bill, COUNT(bill) as cnt
from bills
group by bill
) tmp on tmp.bill = b.bill
答案 1 :(得分:3)
select bill,item,totalPrice,(SELECT
COUNT(b1.bill)
FROM
bills AS b1 where b1.bill= b.bill
GROUP BY bill) AS bill_count from bills AS b