我如何循环使用此JSON
:
[{
"X": "54.6000621",
"Y": "45.8360411",
"Dates": [{
"Date": "2000\/04\/26",
"Time": "12:13:45"
}, {
"Date": "2000\/04\/26",
"Time": "13:13:45"
}, {
"Date": "2000\/04\/26",
"Time": "14:13:12"
}, {
"Date": "2000\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2000\/04\/26",
"Time": "16:13:48"
}],
"Count": 5,
"X": "98.6254621",
"Y": "99.8360411",
"Dates": [{
"Date": "2012\/04\/26",
"Time": "12:13:45"
}, {
"Date": "2012\/04\/26",
"Time": "13:13:45"
}, {
"Date": "2012\/04\/26",
"Time": "14:13:12"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2012\/04\/26",
"Time": "16:13:48"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}],
"Count": 7,
"X": "58.4582621",
"Y": "85.8360411",
"Dates": [],
"Count": 0
}]
答案 0 :(得分:3)
您的回答应该是这样的回答看起来像我的回答
[{
"X": "54.6000621",
"Y": "45.8360411",
"Dates": [{
"Date": "2000\/04\/26",
"Time": "12:13:45"
}, {
"Date": "2000\/04\/26",
"Time": "13:13:45"
}, {
"Date": "2000\/04\/26",
"Time": "14:13:12"
}, {
"Date": "2000\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2000\/04\/26",
"Time": "16:13:48"
}],
"Count": 5
},
{
"X": "98.6254621",
"Y": "99.8360411",
"Dates": [{
"Date": "2012\/04\/26",
"Time": "12:13:45"
}, {
"Date": "2012\/04\/26",
"Time": "13:13:45"
}, {
"Date": "2012\/04\/26",
"Time": "14:13:12"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2012\/04\/26",
"Time": "16:13:48"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}],
"Count": 7
},
{
"X": "58.4582621",
"Y": "85.8360411",
"Dates": [],
"Count": 0
}]
获取价值的代码
try {
JSONArray jsonArray=new JSONArray(response);
for (int i=0;i<jsonArray.length();i++)
{
JSONObject jsonObject=jsonArray.getJSONObject(i);
String X=jsonObject.getString("X");
String Y=jsonObject.getString("Y");
String Count=jsonObject.getString("Count");
JSONArray jsonArraydates=jsonObject.getJSONArray("Dates");
for (int j=0;j<jsonArraydates.length();j++)
{
JSONObject jsonObjectDates=jsonArraydates.getJSONObject(j);
String Date=jsonObjectDates.getString("Date");
String Time=jsonObjectDates.getString("Time");
}
}
} catch (JSONException e) {
e.printStackTrace();
}
答案 1 :(得分:1)
使用多循环概念
try {
JSONArray mArray = new JSONArray("your resonce json string");
for (int index = 0; index < mArray.length(); index++) {
JSONObject mJsonObject = mArray.getJSONObject(0);
JSONArray mDataArray = mJsonObject.getJSONArray("Dates");
for (int row = 0; row < mDataArray.length(); row++) {
JSONObject mDatesObject = mDataArray.getJSONObject(0);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
答案 2 :(得分:1)
你发布的json中有一个错误...
这应该是正确的json ......
[{
"X": "54.6000621",
"Y": "45.8360411",
"Dates": [{
"Date": "2000\/04\/26",
"Time": "12:13:45"
}, {
"Date": "2000\/04\/26",
"Time": "13:13:45"
}, {
"Date": "2000\/04\/26",
"Time": "14:13:12"
}, {
"Date": "2000\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2000\/04\/26",
"Time": "16:13:48"
}],
"Count": 5,
"X": "98.6254621",
"Y": "99.8360411",
"Dates": [{
"Date": "2012\/04\/26",
"Time": "12:13:45"
}, {
"Date": "2012\/04\/26",
"Time": "13:13:45"
}, {
"Date": "2012\/04\/26",
"Time": "14:13:12"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2012\/04\/26",
"Time": "16:13:48"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}, {
"Date": "2012\/04\/26",
"Time": "15:13:10"
}],
"Count": 7,
"X": "58.4582621",
"Y": "85.8360411",
"Dates": [],
"Count": 0
}]