Question

有没有更好的方法在PHP中以三个为一组访问此数组？

假设我的数组是逗号分隔的字符串，如：

("Thora","Birch","Herself","Franklin Delano","Roosevelt","Himself (archive footage)","Martin Luther","King","Himself (archive footage) (uncredited)")

尽管数组最终会变得更大，但每个数组都会有所不同，但仍然是三个逻辑组（名字，姓氏，角色）。

我想要完成的是以三个为一组循环遍历数组，以便第一个记录具有firstname[0]=>"Thora", lastname[0]=>"Birch" and role[0]=>"Herself".

我只习惯foreach循环，但是没有看到像“每3个”这样的额外参数，所以也许有人可以解决这些问题？

Answer 1

PHP有一个名为array_chunk的函数，专门用于此任务。

试试这个：

$sets = array_chunk($people, 3);
foreach ($sets as $set) {
  //you could use the following line to put each field into a nice variable
  list ($firstname, $lastName, $role) = $set;

  //if all you want to do is collect the values, do this 
  $firstNames[] = $set[0];
  $lastNames[] = $set[1];
  $role[] = $set[2];
}

请注意，最后一个块的大小可能不是3，因此如果无法保证数组的长度始终是3的倍数，则应检查键1和2是否设置为isset。

Answer 2

您可以使用for - 循环，假设您的'people'数组的长度为3n。

$people = array("Thora","Birch","Herself","Franklin Delano","Roosevelt","Himself (archive footage)","Martin Luther","King","Himself (archive footage) (uncredited)");
$firstName = array();
$lastName = array();
$role = array();
for($i=0; $i<count($people); $i += 3){
   $firstName[] = $people[$i];
   $lastName[] = $people[$i+1];
   $role[] = $people[$i+2];
}

Answer 3

怎么样伪代码

for Index = 0 index = length index +=3
{
   Firstname= array[index]
   middlename = array[index+1]
   lastname = array[index+2]
   Do Something with them...
}

Answer 4

或者，如果您使用PHP＆gt; = 5.3：

array_walk(
        range(1,9),//<== normally your array, range(1,9) is just an example/test value
        function($value,$key) use (&$return){
                 $return[$key % 3][] = $value;
        });
var_dump($return);

如何从阵列中检索数据，一次3个？

4 个答案: