我在rails应用程序中使用Active模型序列化程序,我想重构显示:
每当我去http://localhost:3000/api/users/1时,我都会看到:
{"data":{"id":"1","type":"users","attributes":{"username":"Iggy1"},"relationships":{"items":{"data":[{"id":"1","type":"items"},{"id":"7","type":"items"}]},"lists":{"data":[{"id":"1","type":"lists"},{"id":"8","type":"lists"},{"id":"14","type":"lists"},{"id":"15","type":"lists"},{"id":"17","type":"lists"}]}}}}
如何让它看起来像:
{
"data": {
"id": "1",
"type": "users",
"attributes": {
"username": "Iggy1"
},
"relationships": {
"items": {
"data": [{
"id": "1",
"type": "items"
}, {
"id": "7",
"type": "items"
}]
},
"lists": {
"data": [{
"id": "1",
"type": "lists"
}, {
"id": "8",
"type": "lists"
}, {
"id": "14",
"type": "lists"
}, {
"id": "15",
"type": "lists"
}, {
"id": "17",
"type": "lists"
}]
}
}
}
}
我花了很多时间浏览adapters,rendering,architecture,但我找不到指南。首先,是否可以使它看起来像上面的第二个代码块?其次,如果可能,我该怎么做才能改变显示?
API / users_controller.rb
def show
@user = User.find_by(id: params[:id])
@no_user_found = User.all #other alternative when user ID not found?
if @user.nil?
flash[:notice] = "No user found"
render json: @no_user_found, each_serializer: UserSerializer
else
render json: @user, each_serializer: UserSerializer
end
end
user_serializer.rb
class UserSerializer < ActiveModel::Serializer
attributes :id, :username#, :email
has_many :items, through: :lists
has_many :lists
end
的routes.rb
Rails.application.routes.draw do
ActiveModelSerializers.config.adapter = :json_api
namespace :api, defaults: { format: :json } do
resources :users do
resources :lists
end
resources :lists, only: [] do
resources :items, only: [:create, :index, :show, :update]
end
resources :items, only: [:destroy]
end
end
答案 0 :(得分:4)
我建议使用Postman而不是使用浏览器
08-02 21:09:35.184 E/AndroidRuntime: FATAL EXCEPTION: main
Process: com.hackmodford.bigfinish, PID: 30986
java.lang.IllegalStateException
at android.media.MediaPlayer.setPlaybackParams(Native Method)
at com.hackmodford.bigfinish.mediaPlayerService.MediaPlayerService.incrementPlaybackRate(MediaPlayerService.java:543)
at com.hackmodford.bigfinish.mediaPlayerService.MediaPlayerService.access$1000(MediaPlayerService.java:47)
at com.hackmodford.bigfinish.mediaPlayerService.MediaPlayerService$3.onCustomAction(MediaPlayerService.java:336)
at android.support.v4.media.session.MediaSessionCompat$Callback$StubApi21.onCustomAction(MediaSessionCompat.java:832)
at android.support.v4.media.session.MediaSessionCompatApi21$CallbackProxy.onCustomAction(MediaSessionCompatApi21.java:231)
at android.media.session.MediaSession$CallbackMessageHandler.handleMessage(MediaSession.java:1246)
at android.os.Handler.dispatchMessage(Handler.java:102)
at android.os.Looper.loop(Looper.java:148)
at android.app.ActivityThread.main(ActivityThread.java:5422)
at java.lang.reflect.Method.invoke(Native Method)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)
。
您可以使用下面的代码使用缩进和换行来渲染它:
pretty_generate
在上面的代码中使用:
<pre><%= JSON.pretty_generate(your_json_here) %></pre>
答案 1 :(得分:0)
你的问题是关于json输出的样式。正如上面提到的@araratan,您可以使用只为您提供可读性。并且没有必要在机器中使用时尚。 如果您需要Generate preety json outpur
中相同的外观