Question

我有两个数据帧。我需要根据unit和date的值将df2.faults列的值复制到df1.faults列。

两个数据帧的长度不同。 df1可能与df2相反的（单位，日期）重复。模仿我的数据集的示例：

    df1 = pd.DataFrame({'unit': ['x']*5+['y']*6 + ['z']*5,
                     'date': ['2016-06-14', '2016-06-14', '2016-06-15', '2016-06-16', '2016-06-16', 
                             '2016-06-14', '2016-06-14', '2016-06-15', '2016-06-15', '2016-06-16', '2016-06-16',
                             '2016-06-15', '2016-06-16', '2016-06-16', '2016-06-17', '2016-06-17'],
                   'faults': None})
df1.date = pd.to_datetime(df1.date)
print(df1)
      date faults unit
0  2016-06-14   None    x
1  2016-06-14   None    x
2  2016-06-15   None    x
3  2016-06-16   None    x
4  2016-06-16   None    x
5  2016-06-14   None    y
6  2016-06-14   None    y
7  2016-06-15   None    y
8  2016-06-15   None    y
9  2016-06-16   None    y
10 2016-06-16   None    y
11 2016-06-15   None    z
12 2016-06-16   None    z
13 2016-06-16   None    z
14 2016-06-17   None    z
15 2016-06-17   None    z

df2 = pd.DataFrame({'unit': ['x']*3+['y']*3 + ['z']*3,
                    'date': ['2016-06-14', '2016-06-15', '2016-06-16', 
                              '2016-06-14', '2016-06-15', '2016-06-16',
                              '2016-06-15', '2016-06-16', '2016-06-17'],
                    'faults': [76, 12, 30, 45, 23, 25, 10, 26, 43]})
df2.date = pd.to_datetime(df2.date)
print(df2)
 date  faults unit
0 2016-06-14      76    x
1 2016-06-15      12    x
2 2016-06-16      30    x
3 2016-06-14      45    y
4 2016-06-15      23    y
5 2016-06-16      25    y
6 2016-06-15      10    z
7 2016-06-16      26    z
8 2016-06-17      43    z

使用嵌套循环所需的输出：

   for u in pd.unique(df2.unit):
     for d in pd.unique(df2[df2.unit == u].date):
        df1.ix[(df1.unit == u)&(df1.date == d) ,'faults'] = int(df2[(df2.unit == u)&(df2.date == d)]['faults'])
   print(df1)
             date faults unit
0  2016-06-14     76    x
1  2016-06-14     76    x
2  2016-06-15     12    x
3  2016-06-16     30    x
4  2016-06-16     30    x
5  2016-06-14     45    y
6  2016-06-14     45    y
7  2016-06-15     23    y
8  2016-06-15     23    y
9  2016-06-16     25    y
10 2016-06-16     25    y
11 2016-06-15     10    z
12 2016-06-16     26    z
13 2016-06-16     26    z
14 2016-06-17     43    z
15 2016-06-17     43    z

我想不出有效的方法！列表理解，条件索引，......？我错过了什么吗？

谢谢！

更新

单循环解决方案

for index, row in df2.iterrows():   
    df1.ix[(df1.unit == row['unit'])&(df1.date == row['date']) ,'faults'] = row['faults']

更有效的解决方案？我的数据集相对较大，我想要完全避免循环。

Answer 1

简单，使用左合并：

df1 = pd.merge(df1,df2,how='left',on=['date','unit'])
df1 =  
         date faults_x unit  faults_y
0  2016-06-14     None    x        76
1  2016-06-14     None    x        76
2  2016-06-15     None    x        12
3  2016-06-16     None    x        30
4  2016-06-16     None    x        30
5  2016-06-14     None    y        45
6  2016-06-14     None    y        45
7  2016-06-15     None    y        23
8  2016-06-15     None    y        23
9  2016-06-16     None    y        25
10 2016-06-16     None    y        25
11 2016-06-15     None    z        10
12 2016-06-16     None    z        26
13 2016-06-16     None    z        26
14 2016-06-17     None    z        43
15 2016-06-17     None    z        43

# Some Bookkeeping
df1 = df1.drop('faults_x',1)
df1.rename(columns={'faults_y':'faults'})

# Final Output
df1 = 
         date unit  faults
0  2016-06-14    x      76
1  2016-06-14    x      76
2  2016-06-15    x      12
3  2016-06-16    x      30
4  2016-06-16    x      30
5  2016-06-14    y      45
6  2016-06-14    y      45
7  2016-06-15    y      23
8  2016-06-15    y      23
9  2016-06-16    y      25
10 2016-06-16    y      25
11 2016-06-15    z      10
12 2016-06-16    z      26
13 2016-06-16    z      26
14 2016-06-17    z      43
15 2016-06-17    z      43

记住你的加入，你会没事的！：）

如果你想一次性去做，那么：

df1 = pd.merge(df1.drop('faults',1),df2,how='left',on=['date','unit'])

有条件地选择和设置列值

更新

1 个答案: