Question

我不知道为什么这会变得无效，我无法弄明白。当我的主管离开时，我得到了一个遗留数据库，我负责直到有人来取代他。我正在尝试运行此查询...

    SELECT     tblM.guidRId, SUM(dbo.tblCH.curTotalCost) AS curValue
FROM         tblCH INNER JOIN
                      tblM ON tblCH.guidMId = tblM.guidMId INNER JOIN
                      ViewLM ON tblM.strNumber = ViewLM.strNumber
WHERE     (tblM.guidRId = '4d832bc8-1827-4054-9896-6111844b0f26')

我一直得到的错误是...... Msg 8120，Level 16，State 1，Line 1 列'tblM.guidRId'在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。

为什么会出现此错误？

Answer 1

因为如果要使用SUM（）[或COUNT，AVG（）等等]聚合函数和另一个非聚合列，需要GROUP BY：

SELECT tblM.guidRId, SUM(dbo.tblCH.curTotalCost) AS curValue
FROM   tblCH 
INNER JOIN tblM 
    ON tblCH.guidMId = tblM.guidMId 
INNER JOIN ViewLM 
    ON tblM.strNumber = ViewLM.strNumber
WHERE  tblM.guidRId = '4d832bc8-1827-4054-9896-6111844b0f26'
GROUP BY tblM.guidRId;

Answer 2

你忘了组guidRId。（您正在汇总数据）

SELECT     
    tblM.guidRId, 
    SUM(dbo.tblCH.curTotalCost) AS curValue
FROM         
    tblCH 
    INNER JOIN tblM ON tblCH.guidMId = tblM.guidMId 
    INNER JOIN ViewLM ON tblM.strNumber = ViewLM.strNumber
WHERE  
    tblM.guidRId = '4d832bc8-1827-4054-9896-6111844b0f26'
GROUP BY tblM.guidRId

Answer 3

尝试：

SELECT
 tblM.guidRId, SUM(dbo.tblCH.curTotalCost) AS curValue
FROM
 tblCH
  INNER JOIN tblM
   ON tblCH.guidMId = tblM.guidMId
  INNER JOIN ViewLM
   ON tblM.strNumber = ViewLM.strNumber
WHERE (tblM.guidRId = '4d832bc8-1827-4054-9896-6111844b0f26')
GROUP BY tblM.guidRId

SQL查询在选择列表中无效

3 个答案: