Question

我已将OneSignal集成到我的Android应用程序中以用于推送通知，所有工作正常并且通知都已通过。但是，为了以自定义方式处理这些通知，我需要更改什么？接收方需要从通知中解析JSON有效负载，并根据收到的内容将用户发送到应用中的正确位置。

Answer 1

您需要设置NotificationOpenedHandler类来处理通知的打开。请参阅以下示例代码进行设置。

import com.onesignal.OneSignal;

public class YourAppClass extends Application {
   @Override
   public void onCreate() {
      super.onCreate();

      OneSignal.startInit(this)
        .setNotificationOpenedHandler(new ExampleNotificationOpenedHandler())
        .init();
   }

  // This fires when a notification is opened by tapping on it or one is received while the app is running.
  private class ExampleNotificationOpenedHandler implements NotificationOpenedHandler {
    @Override
    public void notificationOpened(String message, JSONObject additionalData, boolean isActive) {
      try {
        if (additionalData != null) {
          if (additionalData.has("actionSelected"))
            Log.d("OneSignalExample", "OneSignal notification button with id " + additionalData.getString("actionSelected") + " pressed");

          Log.d("OneSignalExample", "Full additionalData:\n" + additionalData.toString());
        }
      } catch (Throwable t) {
        t.printStackTrace();
      }
    }
}

如果您需要更改应用程序打开时启动的活动，请参阅OneSignal Changing the open action of a notification说明。

在OneSignal通知中处理自定义有效负载

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