Question

构建新客户在进入熟食店时将使用的方法。 take_a_number方法应该接受两个参数，即当前行的数组（katz_deli），以及包含希望加入该行的人的名字的字符串。该方法应该返回该人的姓名及其在线的位置。如何排列以使当前行的数组等于names数组的数量？

＆＃13;

katz_deli = []

def line(array)
  if array[0] == nil
   puts "The line is currently empty."
 end
end

def take_a_number(array, name)
  i=0 
  counter = 1
  while array.count != name.length 
    array[i] = counter
    i+=1 
    counter +=1 
  end
  if array.count > 1
    puts "The line is currently:"
  end
  name.each_with_index {|val, index| puts "#{index+1}. #{val}"}
  end

＆＃13;

这是Rspec文件：

＆＃13;

describe 'Deli Counter' do

  let(:katz_deli) { [] }
  let(:other_deli) { ["Logan", "Avi", "Spencer"] }

  describe "#line" do
    context "there is nobody in line" do
      it "should say the line is empty" do
        # This line checks the current standard output (your terminal screen)
        # to make sure the correct output has been puts'ed.
        expect($stdout).to receive(:puts).with("The line is currently empty.")
        line(katz_deli)
      end
    end

    context "there are people in line" do
      it "should display the current line" do
        expect($stdout).to receive(:puts).with("The line is currently: 1. Logan 2. Avi 3. Spencer")
        line(other_deli)
      end
    end
  end

＆＃13;

Answer 1

我提前做错了方法

＆＃13;

katz_deli = []

def line(array)
  if array.count > 1
   output = "The line is currently:"
   array.each_with_index {|val, index| output << " #{index+1}. #{val}"}
   puts output
   else 
     puts "The line is currently empty."
 end
end

＆＃13;

失败/错误：期望（$ stdout）。接收（：puts）.with

1 个答案: