以下是程序
CREATE DEFINER=`root`@`localhost` PROCEDURE `sitter_price`(
in in_hours float,
in age varchar(100),
in no_of_sitters int,
in no_of_days int
)
BEGIN
select
TRUNCATE(sum(price)*in_hours*no_of_days*no_of_sitters,2) as
total_amount
from job_prices jp
join kids_ages ka on ka.id = jp.kids_age_id
where ka.age in(age) and start_hours > in_hours
AND in_hours <= end_hours;
END
这个过程中的问题是我将如何传入age varchar(100),参数in,in子句 目前我正在使用查询解析
CALL `usitterz`.`sitter_price`(4.10,'1,2,3,4', 3, 5);
但这是错误的,因为在查询中读取它像('1,2,3,4'),但我希望它像 - (1,2,3,4)。
就像
CREATE DEFINER=`root`@`localhost` PROCEDURE `sitter_price`(
in in_hours float,
in age varchar(100),
in no_of_sitters int,
in no_of_days int
)
BEGIN
select
TRUNCATE(sum(price)*in_hours*no_of_days*no_of_sitters,2) as
total_amount
from job_prices jp
join kids_ages ka on ka.id = jp.kids_age_id
where ka.age in(1,2,3,4) and start_hours > in_hours
AND in_hours <= end_hours;
END
答案 0 :(得分:1)
第1步:乱七八糟地获取EXECUTE
DROP PROCEDURE IF EXISTS sitter_price;
DELIMITER $
CREATE DEFINER=`root`@`localhost` PROCEDURE `sitter_price`(
in in_hours float,
in age varchar(100),
in no_of_sitters int,
in no_of_days int
)
BEGIN
SET @theSql=CONCAT('SELECT TRUNCATE(sum(price)*',in_hours,'*',no_of_days,'*',no_of_sitters,',2)');
SET @theSql=CONCAT(@theSql,' as total_amount from job_prices jp join kids_ages ka on ka.id = jp.kids_age_id');
SET @theSql=CONCAT(@theSql,' where ka.age in(',age,') and start_hours > ',in_hours,' AND ');
SET @theSql=CONCAT(@theSql,in_hours,'<= end_hours');
/*
select
TRUNCATE(sum(price)*in_hours*no_of_days*no_of_sitters,2) as
total_amount
from job_prices jp
join kids_ages ka on ka.id = jp.kids_age_id
where ka.age in(1,2,3,4) and start_hours > in_hours
AND in_hours <= end_hours;
*/
select @theSql;
END$
DELIMITER ;
Step2:传入参数以查看字符串是什么样的
call sitter_price(89,'1,2,4,8',11,12);
SELECT TRUNCATE(sum(price)*89*12*11,2) as total_amount
from job_prices jp
join kids_ages ka on ka.id = jp.kids_age_id
where ka.age in(1,2,4,8) and start_hours > 89
AND 89<= end_hours
步骤3:使用PREPARE
和EXECUTE
最终确定存储过程。
DROP PROCEDURE IF EXISTS sitter_price;
DELIMITER $
CREATE DEFINER=`root`@`localhost` PROCEDURE `sitter_price`(
in in_hours float,
in age varchar(100),
in no_of_sitters int,
in no_of_days int
)
BEGIN
SET @theSql=CONCAT('SELECT TRUNCATE(sum(price)*',in_hours,'*',no_of_days,'*',no_of_sitters,',2)');
SET @theSql=CONCAT(@theSql,' as total_amount from job_prices jp join kids_ages ka on ka.id = jp.kids_age_id');
SET @theSql=CONCAT(@theSql,' where ka.age in(',age,') and start_hours > ',in_hours,' AND ');
SET @theSql=CONCAT(@theSql,in_hours,'<= end_hours');
PREPARE stmt from @theSql; -- create a prepared stmt from the above concat
EXECUTE stmt; -- run it
DEALLOCATE PREPARE stmt; -- cleanup
END$
DELIMITER ;
MySqL手册页SQL Syntax for Prepared Statements。
请注意,上述CONCAT()
只有使用用户变量(带有@
符号)才能成功。不是DECLARE
的本地变量。
答案 1 :(得分:0)
以下是我自己的问题的答案
CREATE PROCEDURE `sitter_price`(
in in_hours float,
in age varchar(100),
in no_of_sitters int,
in no_of_days int
)
BEGIN
select
TRUNCATE(sum(price)*in_hours*no_of_days*no_of_sitters,2) as total_amount
from job_prices jp
join kids_ages ka on ka.id = jp.kids_age_id
where
jp.status = 1 and
find_in_set(ka.age,age) and
in_hours between jp.start_hours and jp.end_hours;
END
通话程序
CALL `usitterz`.`sitter_price`(6, '1,2,3,4', 1, 5);
答案 2 :(得分:0)
另一个答案
CREATE DEFINER=`root`@`localhost` PROCEDURE `sitter_price`(
in in_hours float,
in age varchar(100),
in no_of_sitters int,
in no_of_days int
)
BEGIN
SET @theSql=CONCAT('SELECT TRUNCATE(sum(price)*',in_hours,'*',no_of_days,'*',no_of_sitters,',2)');
SET @theSql=CONCAT(@theSql,' as total_amount from job_prices jp join kids_ages ka on ka.id = jp.kids_age_id');
SET @theSql=CONCAT(@theSql,' where ka.age in(',age,') and ' ,in_hours, ' between jp.start_hours and jp.end_hours ');
PREPARE stmt from @theSql; -- create a prepared stmt from the above concat
EXECUTE stmt; -- run it
DEALLOCATE PREPARE stmt; -- cleanup
END