Question

这是我的代码。我执行然后什么也没发生。请检查我的代码

$id = trim(htmlentities($_REQUEST['id'],ENT_QUOTES)); //call the action from previous page

//fetch data
$stmt = $dbi->prepare("SELECT a.telco, a.no_siri, a.no_topup, a.amount, a.requestingAgentID, a.requestDateTime, a.isUsed, b.name FROM card_telco a LEFT JOIN agents b ON a.requestingAgentID = b.id WHERE id = ?"); //query
$stmt->bind_param('s', $id); //binding
mysqli_stmt_execute($stmt); //execute
mysqli_stmt_store_result($stmt); //store the result
$count = mysqli_stmt_num_rows($stmt); //execute rows
$stmt->bind_result($newTelco, $noSiri, $noTopup, $newAmount, $newRequestAgentID, $newRequestDateTime, $isUsing, $newName, $agendId); //binding new result
$stmt->execute() or die(mysqli_error()); //execute the statement
$stmt->store_result() //store new result
$stmt->fetch(); //fetch the data
$stmt->close(); //close the statement

ChromePhp::log('here'); //console
ChromePhp::log($newTelco, $noSiri); //console

Answer 1

好的，我明白了！我的查询错了。

选择a.id，a.telco，a.no_siri，a.no_topup，a.amount，a.requestingAgentID，a.requestDateTime，a.isUsed，b.name FROM card_telco a LEFT JOIN agent b on a.requestingAgentID = b.id WHERE a.id =？

这是我的新查询。谢谢你的帮助

PHP Mysqli。需要从表中获取数据

1 个答案: