我在sql查询时遇到问题。我需要花费最近30天,然后仅删除4个结果,其中“投票”值更大
db结构
Id | time | voting
1 | unix time | 3
2 | unix time | 2
3 | unix time | 4
4 | unix time | 1
5 | unix time | 6
我想带我的数据只有:5-3-1-2
我试过
select a.*
from table a
inner join
( select votingng, max(time) as latest from table group by voting) v
on a.time = v.latest
and a.voting = v.voting
order by time desc limit
答案 0 :(得分:1)
我认为这就是你想要的:
select v.*
from voting v
where timestamp >= unix_timestamp(date_sub(curdate(), interval 1 month)
order by voting desc
limit 4;
答案 1 :(得分:1)
听起来你正试图在过去30天内获得前4名投票结果。这些中的任何一个都能满足您的需求吗?
SELECT a.*
FROM table a
WHERE a.time > UNIX_TIMESTAMP(DATE_SUB(CURDATE(), INTERVAL 30 DAY))
ORDER BY a.voting DESC
LIMIT 4;
或
SELECT a.*
FROM table a
WHERE DATEDIFF( NOW(), FROM_UNIXTIME(a.time) ) <= 30
ORDER BY a.voting DESC
LIMIT 4;
答案 2 :(得分:0)
希望这就是你要找的东西:
Select *
From
Voting
Where
time Between CURDATE() And DATE_SUB(CURDATE(),INTERVAL 30 DAY)
Order By voting Desc
Limit 4
答案 3 :(得分:0)
如果您使用的是teradata
,请尝试此操作SELECT * from table
qualify row_number () over(order by time desc)=1 ;
或
select * from
(select table.*, row_number () over(order by time desc) as RANK from table)
where RANK=1