Question

我正在创建一个查询，以发送批量电子邮件应用XML，其中包含组装相应电子邮件所需的所有内容。我似乎无法使嵌套元素正常工作。

我正在尝试获取类似

的XML

    <EmailsToBeSent>
        <EmailToBeSent>
            <ReferenceId>1</ReferenceId>
                <Tags>
                    <Tag>
                        <Name>ToAddress</Name>
                        <Value>blah@blah.com</Value>
                    </Tag>
                    <Tag>
                        <Name>CCAddress</Name>
                        <Value>yadda@yadda.com</Value>
                    </Tag>
                    <Tag>
                        <Name>FromAddress</Name>
                        <Value>me@me.com</Value>
                    </Tag>
                </Tags>
            <SomethingElse>'asASas'</SomethingElse>                
        </EmailToBeSent>
    </EmailsToBeSent>

到目前为止，我得到的最接近的是：

SELECT  
    ReferenceId,
    (SELECT
         'ToAddress' AS "Tag/Name",
         ToAddress AS "Tag/Value",
         'CCAddress' AS "Tag/Name",
         CCAddress AS "Tag/Value",
         'FromAddress' AS "Tag/Name",
         FromAddress AS "Tag/Value"
     FROM 
         EmailTable AS ET
     WHERE 
         ET.ReferenceId = RT.ReferenceId
     FOR XML PATH('Tags'), TYPE), 
    'asASas' AS SomethingElse
FROM 
    RefTable AS RT
FOR XML PATH('EmailToBeSent'), ROOT('EmailsToBeSent')

结果是：

<EmailsToBeSent>
    <EmailToBeSent>
        <ReferenceId>1</ReferenceId>
        <Tags>
            <Tag>
                <Name>ToAddress</Name>
                <Value>blah@blah.com</Value>
                <Name>CCAddress</Name>
                <Value>yadda@yadda.com</Value>
                <Name>FromAddress</Name>
                <Value>me@me.com</Value>
            </Tag>
        </Tags>
        <SomethingElse>'asASas'</SomethingElse>                
    </EmailToBeSent>
</EmailsToBeSent>

Answer 1

只需在群组之间添加分隔符。

SELECT  ReferenceId
    , (SELECT 'ToAddress'     AS "Tag/Name"
              , ToAddress     AS "Tag/Value"
              , null          AS "separator"
              , 'CCAddress'   AS "Tag/Name"
              , CCAddress     AS "Tag/Value"
              , null          AS "separator"
              , 'FromAddress' AS "Tag/Name"
              , FromAddress   AS "Tag/Value"
        FROM EmailTable AS ET
        WHERE ET.ReferenceId = RT.ReferenceId
        FOR XML PATH('Tags'),TYPE
        )
    , 'asASas' AS SomethingElse

FROM RefTable AS RT
FOR XML PATH('EmailToBeSent'), ROOT('EmailsToBeSent')

SQL XML嵌套元素

1 个答案: