Question

我正致力于记忆游戏。我想在两行中显示卡片的图像。除第二行中的第一张卡外，所有卡都正确显示。运行此代码需要使用CodeSkulptor。整个计划在这里： http://www.codeskulptor.org/#user41_a22429Vx58_2.py

def draw(canvas):
    global deck, cards, WIDTH, HEIGHT
    num_start = 10
    w = 67
    h = 100
    center_source = [w // 2, h // 2]
    center_dest = [w // 2, h // 2]
    for c in deck:
        for card in cards:
            if card == c:
                if center_dest[0] <= WIDTH:
                    canvas.draw_image(cards[card], (center_source), (w , h), (center_dest), (w, h))
                    center_dest[0] += w + 2
                elif center_dest[0] > WIDTH:
                    center_dest = [w // 2, h // 2 + h]
                    canvas.draw_image(cards[card], (center_source), (w , h), (center_dest), (w, h *2))
                    center_dest[0] += w + 2

Answer 1

当center_dest需要重置其水平位置时，您的elif条件仅触发1次。这是canvas.draw_image(cards[card], (center_source), (w , h), (center_dest), (w, h *2))调用h * 2导致不正确绘制的地方。

如果您删除*2，它将有效。您还可以按如下方式重构逻辑，这样您就不会重复绘制：

if center_dest[0] > WIDTH:
    center_dest = [w // 2, h // 2 + h]
canvas.draw_image(cards[card], (center_source), (w , h), (center_dest), (w, h))
center_dest[0] += w + 2

要使其可扩展为任意数量的行，请将更新更改为：

if center_dest[0] > WIDTH:
    center_dest[0] = w // 2
    center_dest[1] += h

为什么代码适用于所有图像，第一个图像除外？

1 个答案: