我有一个数组如下:
let allCars = [
{
id: 1,
listID: 2,
name: "CAR 1",
url: "Fixed 2016-W24"
}, {
id: 2,
listID: 2,
name: "CAR 2",
url: "Fixed 2016-W24"
}, {
id: 3,
listID: 3,
name: "CAR 3",
url: "Fixed 2016-W24"
},{
id: 1,
listID: 1,
name: "CAR 4",
url: "Fixed 2016-W24"
},{
id: 5,
listID: 2,
name: "CAR 5",
url: "Fixed 2016-W24"
}
];
我还有卡片中的一系列汽车,如下所示:
let cardContent = [
{
carID: 1,
listID: 2
},
{
carID: 5,
listID: 2
}
]
我试图从allCars获得id=1, listID=2
和id=5, listID=2
的汽车。
我尝试通过cardContent进行映射,然后仅过滤那些来自allCars的carID和列表ID的人。但没有成功。
我试过这样的事情
const result = allCars.map(i => {
return {
carID: i.carID,
listID: i.listID
}
}).filter(a => {
return ((a.carID === cardContent.carID) && (a.listID === cardContent.listID))
});
这是jsfiddle
。
有什么建议吗?
答案 0 :(得分:1)
您可以使用Array#filter
和Array#some
let allCars = [{"id":1,"listID":2,"name":"CAR 1","url":"Fixed 2016-W24"},{"id":2,"listID":2,"name":"CAR 2","url":"Fixed 2016-W24"},{"id":3,"listID":3,"name":"CAR 3","url":"Fixed 2016-W24"},{"id":1,"listID":1,"name":"CAR 4","url":"Fixed 2016-W24"},{"id":5,"listID":2,"name":"CAR 5","url":"Fixed 2016-W24"}];
let cardContent = [{"carID":1,"listID":2},{"carID":5,"listID":2}]
const result = allCars.filter(function(e) {
return cardContent.some(function(a) {
return e.id == a.carID && e.listID == a.listID;
})
})
console.log(result);
答案 1 :(得分:0)
试试这个:
let allCars = [
{
id: 1,
listID: 2,
name: "CAR 1",
url: "Fixed 2016-W24"
}, {
id: 2,
listID: 2,
name: "CAR 2",
url: "Fixed 2016-W24"
}, {
id: 3,
listID: 3,
name: "CAR 3",
url: "Fixed 2016-W24"
},{
id: 1,
listID: 1,
name: "CAR 4",
url: "Fixed 2016-W24"
},{
id: 5,
listID: 2,
name: "CAR 5",
url: "Fixed 2016-W24"
}
];
let cardContent = [
{
carID: 1,
listID: 2
},
{
carID: 5,
listID: 2
}
]
const output = allCars.filter(car => cardContent.some(card => (car.id === card.carID && car.listID === card.listID)));
console.log(output);