Question

我将如何使用if..else，do..while？

此程序应提示用户输入大学名称并输出大学的排名，如果用户输入的名称不正确，程序应输出一条消息，表明输入的名称不正确。

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string college[] = {"Baylor", "Colorado", "Iowa State",
                        "Kansas", "Kansas State", "Missouri",
                        "Nebraska", "Oklahoma", "Oklahoma State",
                        "Texas", "Texas A&M", "Texas Tech"};
    int conferenceRanking[] = {12, 11, 10, 9, 5, 8,
                                3, 2, 7, 1, 6, 4};

    for (if)
    {
        cout << "Enter the name of a Big Twelve College: " << college[count]
         << college << "\n's ranking is " << conferenceRanking[count]
         << "\n" << endl;
    }

    return 0;
}

[样本]这是我想要的输出

Enter the name of a Big Twelve College: Nebraska
Nebraska's ranking is 3

Answer 1

我会采用更复杂的方式并使用地图来保存数据并从命令行std :: getline获取学院，因为它会检测空格并将它们放入字符串中。阅读完名称之后，它会迭代已经创建的地图，找到我们正在寻找的大学。然后检查迭代器是否被找到！您应该查看一些C ++教程或一本好书来学习C ++的基础知识。

（这种方法使用C ++ 11标准，因此请确保您的编译器兼容）

#include <iostream>
#include <string>
#include <map>

int main()
{
        std::map<std::string, int> colleges = {
            {"Baylor", 12},
            {"Colorado", 11},
            {"Iowa State", 10},
            {"Kansas", 9},
            {"Kansas State", 5},
            {"Missouri", 8},
            {"Nebraska", 3},
            {"Oklahoma", 2},
            {"Oklahoma State", 7},
            {"Texas", 1},
            {"Texas A&M", 6},
            {"Texas Tech", 4}
        };

        std::cout << "to end enter: exit";

        bool p = true;
        while(p){
            std::string name;

            std::cout << "Enter the name of a Big Twelve College: ";
            std::getline(std::cin, name);

            if(name == "exit"){
                    p = false;
                    break;
            }

            std::map<std::string, int>::iterator it = colleges.find(name);
            if (it != colleges.end()){
                    std::cout << it->first << "'s ranking is " << it->second << "!" << std::endl;
            }else{
                    std::cout << "No college found!, try again!" << std::endl;
            }
        }

        return 0;
}

Answer 2

您可以使用地图来保存您的排名，这将有助于您轻松地按名称访问您的排名。您还可以保留一个布尔变量，指示当前用户输入是否存在于您的列表中，并使用它来决定用户是否应该获得他/她的答案，或者再次提示您输入一些大学名称。

以下是一个示例主要功能：

#include <iostream>
#include <string>
#include <unordered_map>
using namespace std;

int main()
{
 std::unordered_map<std::string, int> collegeRanks = {
    {"Baylor",12},
    {"Colorado",11},
    {"Iowa State",10}
};
//etc...

bool finished = false; 
string userInput;

while(!finished){

    cout << endl << "Enter the name of a Big Twelve College: ";
    getline (std::cin,userInput);
    std::unordered_map<std::string,int>::const_iterator nameAndRank = collegeRanks.find (userInput);
    if ( nameAndRank == collegeRanks.end() ){
        // Not found :(
        finished = false;
        cout << endl << userInput << " does not exist in our database... try another college name!" << endl;
        userInput = "";
    }
    else{
        // Found :) 
        finished = true;
        cout << userInput << "'s rank is " << std::to_string(nameAndRank->second) << endl;
    }

}

return 0;
}

Answer 3

您只需使用您拥有的阵列即可，而无需使用地图（如果您愿意）。请考虑以下代码。

bool has = false; 
cout << "Enter college name\n";
string name;
cin >> name;
for(int i=0; i<12; i++){
    if(college[i].compare(name) == 0){
        has = true;
        cout << "Ranking of " << college[i] << " is " << conferenceRanking[i];
    }
}
//check if the name entered by user exists
if(has == false)
cout << "The college name entered does not exist";

bool变量has确定用户输入的大学名称是否存在于数组college[]中。如果找到匹配项，则has的值将更改为true。

如何检查输入值是否与数组中的任何值匹配

3 个答案: