Question

我使用对象映射器映射我的类User：

class User: Mappable{

private var _username: String! = nil
private var _password: String! = nil
private var _firstName: String! = nil
private var _lastName: String! = nil

//here are getters and setters(it takes too much space)

init(){

}

required init?(_ map: Map) {

}

func mapping(map: Map) {

    username <- map["USERNAME"]
    password <- map["PASSWORD"]
    firstName <- map["FIRST_NAME"]
    lastName <- map["LAST_NAME"]

  }
}

然后我尝试创建新用户并添加一些值，映射整个对象并像这样发送Alamofire：

let userEmail = userEmailField.text!
let userPassword = userPasswordField.text!

let user = User()
user.username = userEmail
user.password = userPassword
let JSONString = Mapper().toJSONString(user, prettyPrint: true)

AlamofireService.alamofireService.makePostServiceRequest(URL_BASE, parameters: JSONString, resposeCallback: self)

我按照库的说明操作，但是我收到了错误＆＃34;无法转换类型＆＃39;字符串的值？＆＃39;预期的参数类型＆＃39; [String：AnyObject]＆＃39;＆＃34;，为什么？

Answer 1

Alamofire请求以[String：AnyObject]格式获取参数，因此您只需要将字典作为参数传递。在你的情况下，你只需要：

let userEmail = userEmailField.text!
let userPassword = userPasswordField.text!

var dictParameter: Dictionary<String, AnyObject> = [:]
dictParameter["USERNAME"]   = userEmail
dictParameter["PASSWORD"]   = userPassword

之后只需提出请求：

AlamofireService.alamofireService.makePostServiceRequest(URL_BASE, parameters: dictParameter, resposeCallback: self)

Answer 2

您不需要将参数转换为字符串，只需将参数作为字典传递给Alamofire。

无法转换类型＆＃39;字符串的值？＆＃39; （Alamofire）

2 个答案: