我想抓取链接的抓取图片:“http://vnexpress.net/photo/cuoc-song-do-day/nguoi-trung-quoc-ra-be-boi-danh-mat-chuoc-tranh-nong-3445592.html”但是代码只抓取图片(在我的计算机中)并抓取所有图片(在我的朋友计算机中)。请帮帮我
import scrapy
from scrapy.contrib.spiders import Rule, CrawlSpider
from scrapy.contrib.linkextractors import LinkExtractor
from imgur.items import ImgurItem
class ImgurSpider(CrawlSpider):
name = 'imgur'
allowed_domains = ['vnexpress.net']
start_urls = ['http://vnexpress.net/photo/cuoc-song-do-day/nguoi-trung-quoc-ra-be-boi-danh-mat-chuoc-tranh-nong-3445592.html']
# rules = [Rule(LinkExtractor(allow=['/*']), 'parse123')]
def parse(self, response):
image = ImgurItem()
# image['title'] = response.xpath(\
# "//img[data-notes-url=""]").extract()
rel = response.xpath("//div[@id='article_content']//img/@src").extract()
image['image_urls'] = [rel[0]]
return image
答案 0 :(得分:0)
rel = response.xpath("//div[@id='article_content']//img/@src").extract()
image['image_urls'] = [rel[0]]
通过指定[0]索引只能获取一个链接。 试试
image['image_urls'] = rel
您还可以将代码拆分为url解析函数,以及下载图像的回调。