我试图将表单中输入的名称大写并显示
控制器:
package yo;
import javax.servlet.http.HttpServletRequest;
import org.springframework.stereotype.Controller;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;
@Controller
public class HelloWorldController {
@RequestMapping("/")
public String showPage(){
return "helloworld";
}
@RequestMapping("/showForm")
public String showForm(){
return"form";
}
@RequestMapping("/traitement")
public String processForm(){
return"traitement";
}
@RequestMapping("/traitementTwo")
public String caps(HttpServletRequest request,Model model){
String theName=request.getParameter("s");
String result="YO "+theName.toUpperCase();
model.addAttribute("message", result);
return"helloworld";
}
}
form.jsp:
<body>
hello <form action="traitementTwo.jsp" method="GET">
<input type="text" name="s" placeholder="who are u ?" />
<input type="submit"/>
</form>
</body>
</html>
的helloWorld.jsp:
<html>
<body>
the time on the server is <%= new String("Hello World").toUpperCase() %>
<br>
The message :${message}
</body>
</html>
spring-mvcdemo-servlet:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<!-- Step 3: Add support for component scanning -->
<context:component-scan base-package="yo" />
<!-- Step 4: Add support for conversion, formatting and validation support -->
<mvc:annotation-driven/>
<!-- Step 5: Define Spring MVC view resolver -->
<bean
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/view/" />
<property name="suffix" value=".jsp" />
</bean>
</beans>
web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
id="WebApp_ID" version="3.1">
<display-name>mvc</display-name>
<!-- Spring MVC Configs -->
<!-- Step 1: Configure Spring MVC Dispatcher Servlet -->
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-mvc-demo-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Step 2: Set up URL mapping for Spring MVC Dispatcher Servlet -->
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
输出:
Etat HTTP 404 - /mvc/traitementTwo.jsp 类型Rapport d''état
消息/mvc/traitementTwo.jsp
描述La ressourcedemandéen''estpas disponible。
Apache Tomcat / 8.0.36
答案 0 :(得分:1)
听起来您可能没有正确设置web.xml以创建servlet上下文等。
请参阅以下项目:https://www.mkyong.com/spring-mvc/spring-mvc-and-list-example/
在src-&gt; main-&gt; webapp
中具有以下结构/ - web.xml
/ - mvc-dispatcher-servlet.xml
/ pages(存储jsp页面的目录)
否则请发布您的webapp或spring boot配置以确认您已正确设置。
答案 1 :(得分:0)
您已经使用Spring-MVC进行开发,但是您没有Spring MVC配置XML文件。你应该创建一个spring-mvc.xml来配置一些关于spring mvc
的消息答案 2 :(得分:0)
好的,我想我知道问题是什么..在你的form.jsp中:
<form action="traitementTwo.jsp" method="GET">
应该是:
<form action="traitementTwo" method="GET">