Question

我无法使用 json_decode 将此JSON响应解码为PHP，感谢您的帮助：

来自API的JSON响应

{
      "fixtures": [
        {
          "id": 59757,
          "home_team_id": 24,
          "away_team_id": 18,
          "home_score_penalties": 0,
          "away_score_penalties": 0,
              "formation": {
               "home": null,
               "away": null
              },
          "date_time_tba": false,
          "spectators": null,
          "round_id": 4839
        }
      ]
    }

PHP：

$url = "https://api....";
$data = json_decode(file_get_contents($url), true);
echo $data['fixtures'][0]['home_team_id'];
echo $data['formation'][0]['home'];

我没有结果！

谢谢。

Answer 1

那里有JSON验证器的镜像。在使用json_decode之前使用其中任何一个。

{
    "fixtures": [{
        "id": 59757,
        "home_team_id": 24,
        "away_team_id": 18,
        "home_score_penalties": 0,
        "away_score_penalties": 0,
        "formation": {
            "home": null,
            "away": null
        },
        "date_time_tba": false,
        "spectators": null,
        "round_id": 4839,
    }]
}

您的示例无法使用有效的JSON，因为"round_id": 4839,最终不能使用逗号。有效的JSON将是：

{
    "fixtures": [{
        "id": 59757,
        "home_team_id": 24,
        "away_team_id": 18,
        "home_score_penalties": 0,
        "away_score_penalties": 0,
        "formation": {
            "home": null,
            "away": null
        },
        "date_time_tba": false,
        "spectators": null,
        "round_id": 4839
    }]
}

现在这个JSON在解码后返回一个数组：

$json = '{"fixtures": [{"id": 59757,"home_team_id": 24,"away_team_id": 18,"home_score_penalties": 0,"away_score_penalties": 0,"formation": {"home": null,"away": null},"date_time_tba": false,"spectators": null,"round_id": 4839}]}';

var_dump(json_decode($json, true));

结果：

array(1) {
  ["fixtures"]=>
  array(1) {
    [0]=>
    array(9) {
      ["id"]=>
      int(59757)
      ["home_team_id"]=>
      int(24)
      ["away_team_id"]=>
      int(18)
      ["home_score_penalties"]=>
      int(0)
      ["away_score_penalties"]=>
      int(0)
      ["formation"]=>
      array(2) {
        ["home"]=>
        NULL
        ["away"]=>
        NULL
      }
      ["date_time_tba"]=>
      bool(false)
      ["spectators"]=>
      NULL
      ["round_id"]=>
      int(4839)
    }
  }
}

Answer 2

首先检查您是否正在接收var_dump(file_get_contents($url))的输出。

然后验证返回的字符串是否为有效的JSON。由Nordenheim解释here

一旦确认其有效，请检查JSON解码数据以了解如何访问正确的值。

var_dump(json_decode(file_get_contents($url)));

所以以下内容应该是你要找的;

$data = json_decode(file_get_contents($url)); echo $data['data'][0]['id'];;

使用PHP解码多个JSON响应

2 个答案: