Question

我有3个数组，我试图并行打印相应的字符串。 Ruby的新手。不确定我是否应该连接？我真的很想创建一张桌子，但我不知道怎么做。

我目前的代码：

name = ["Buffy Summers", "Willow Rosenberg", "Xander Harris"]
age = ["17", "16", "18"]
hair_color = ["blonde", "red", "brown"]

print name[0]
print " "
print age[0] 
print " "
puts hair_color[0]

print name[1]
print " "
print age[1] 
print " "
puts hair_color[1]

print name[2]
print " "
print age[2] 
print " "
puts hair_color[2]

输出如下：

Buffy Summers 17 Blonde
Willow Rosenberg 16 Red
Xander Harris 18 Brown

我真的很喜欢他们对齐。我意识到我也应该循环。我是初学者。

我想要输出：

Buffy Summers    17  Blonde
Willow Rosenberg 16  Red
Xander Harris    18  Brown

Answer 1

要获得所需的对齐方式，请访问String#%。

max = name.group_by(&:length).max.first

name.zip(age, hair_color).each do |name, age, hair_color|
  puts "%-#{max}s %s %s" % [name, age, hair_color]
end

=> Buffy Summers    17 blonde
=> Willow Rosenberg 16 red
=> Xander Harris    18 brown

Answer 2

假设您的数据包含在以下四个数组中。

name       = ["Buffy Summers", "Willow Rosenberg", "Xander Harris", "Granny", "Lucy"]
age        = ["17", "16", "18", "101", "7"]
hair_color = ["blonde", "red", "brown", "white", "purple"]    
col_fmt    = [{justify: :L, pad: 4}, {justify: :R, pad: 2}, {justify: :L, pad: 3}]

然后你可以按照以下方式打印。

arr = [name, age, hair_color]
columns = col_fmt.zip(arr.map { |a| a.max_by(&:size).size }).
  map { |h, sz| h.merge(width: sz) }
  #=> [{:justify=>:L, :pad=>4, :width=>16}, {:justify=>:R, :pad=>2, :width=>3},
  #    {:justify=>:L, :pad=>3, :width=>6}] 
arr.transpose.each do |a|
  a.zip(columns).each do |attr, fmt|
    print ' ' * fmt[:pad]
    print fmt[:justify] == :L ? attr.ljust(fmt[:width]) : attr.rjust(fmt[:width])
  end
  puts
end
#     Buffy Summers      17   blonde
#     Willow Rosenberg   16   red   
#     Xander Harris      18   brown 
#     Granny            101   white 
#     Lucy                7   purple

Answer 3

请执行以下操作

name = ["Buffy Summers", "Willow Rosenberg", "Xander Harris"]
age = ["17", "16", "18"]
hair_color = ["blonde", "red", "brown"]

~~name.count.times do | index |~~
~~put“＃{name [index]}＃{age [index]}＃{hair_color [index]}”~~
<删除>端

name.count.times do |index|
  printf "%-20s %-2s %-10s\n", name[index],age[index] , hair_color[index]
end

Ruby：如何并行地从数组中打印字符串

3 个答案: