laravel 5.2
我有以下多个auth Gard
Admin Clients Employee
我有
ItemController
->index.blade.php
->create.blade.php
->edit.blade.php
ItemKitController
->index.blade.php
->create.blade.php
->edit.blade.php
我想使用Client和Employee Guard来访问相同的Controller并查看上面提到的内容。
是他们任何可行的方式。
答案 0 :(得分:3)
也许你想要这样的东西
public function __construct()
{
$this->middleware('auth:Admin,Clients,Employee');
}
控制器中的
答案 1 :(得分:0)
您可以使用以下中间件:
Route::group([ 'middleware' => ['Admin', 'Clients', 'Employee'] ], function(){
Route::get('/Admin', 'AdminController@index');
Route::get('/Clients', 'ClientsController@index');
Route::get('/Employee', 'EmployeeController@index');
});
例如,我有一个管理中间件,用于检查用户ID是否为1
<?php
namespace App\Http\Middleware;
use Closure;
use Auth;
use Log;
class AuthAdmin
{
private $admins; // Admin ids
/**
* Handle an incoming request.
*
* @param \Illuminate\Http\Request $request
* @param \Closure $next
* @return mixed
*/
public function handle($request, Closure $next)
{
$this->admins = config('custom.admins'); // get configs
$user = Auth::user();
if($user->id != 1)){
// not admin, redirect home
return redirect('/');
}
// is admin, let request continue
return $next($request);
}
}
然后你必须把它添加到Kernel.php“$ routeMiddleware”:
protected $routeMiddleware = [
'auth' => \App\Http\Middleware\Authenticate::class,
'auth.basic' => \Illuminate\Auth\Middleware\AuthenticateWithBasicAuth::class,
'can' => \Illuminate\Foundation\Http\Middleware\Authorize::class,
'guest' => \App\Http\Middleware\RedirectIfAuthenticated::class,
'throttle' => \Illuminate\Routing\Middleware\ThrottleRequests::class,
// Custom Middleware
// Auth Admin
'auth_admin' => \App\Http\Middleware\AuthAdmin::class,
];
然后在我的路线中:
Route::group([ 'middleware' => ['auth_admin'] ], function(){
// nobody can come to these routes but admins
Route::get('/admin/index', 'AdminController@index');
});