Question

请帮助我是java和android的新手。

以下是字符串数组资源

的示例

的strings.xml

<resources>
   <string-array name="dance_steps">
       <item>Step1</item>
       <item>Step2</item>
       <item>Step3</item>
       <item>Step4</item>
   </string-array>
</resources>

如何获取字符串并将其放在java代码中的不同TextView上？

 TextView step1, step2, step3, step4;
 step1 = (TextView) findViewById(R.id.textview1);
 step2 = (TextView) findViewById(R.id.textview2);
 step3 = (TextView) findViewById(R.id.textview3);
 step4 = (TextView) findViewById(R.id.textview4);

 Resources res = getResources();
 String[] steps = res.getStringArray(R.array.dance_steps);

 step1.setText(item number 1 in String Array);
 step2.setText(item number 2 in String Array);
 step3.setText(item number 3 in String Array);
 step4.setText(item number 4 in String Array);

三江源。

Answer 1

step1.setText(steps[0]);
step2.setText(steps[1]);
step3.setText(steps[2]);
step4.setText(steps[3]);

你应该学习Java基础知识

Answer 2

你只需要传递字符串数组。这是更高效的代码 -

Map<String, String> users = new HashMap<>();
// here when read every line from file, split the line with "-"
// and store it in the map
String[] strs = line.split("-");
users.put(strs[0], strs[1]);

// then when you check, you can do as below
if (users.containsKey(name)) {
    System.out.println("Phone: "+users.get(name));
}

Answer 3

TextView step[] = new TextView[4];
step[0] = (TextView) findViewById(R.id.textview1);
step[1] = (TextView) findViewById(R.id.textview2);
step[2] = (TextView) findViewById(R.id.textview3);
step[3] = (TextView) findViewById(R.id.textview4);

Resources res = getResources();
String[] steps = res.getStringArray(R.array.dance_steps);

for(int i = 0 ; i < steps.length ; i++){
    step[i].setText(steps[i]);
}

如何获取字符串数组中的项目并将其放在不同的TextView上

3 个答案: