使用php

Question

我想提取文件夹中的所有zip文件。所以请检查我的下面的片段并帮助我。

<?php
$path='C:\xampp\htdocs\m'; // folder name 
if ($handle = opendir($path)){
    while (false !== ($file = readdir($handle))){
        if ('.' === $file) continue;
        if ('..' === $file) continue;
        //echo "filename: ".$file."<br />";

        $zip = new ZipArchive;
        $res = $zip->open($file);
        if ($res === TRUE){
            $zip->extractTo($path);   // extract it to the path 
            $zip->close();
            echo " Done! $file extracted to $dir"; // done
        } 
        else{
            echo "opps! I couldn't open $file"; // no
        }
    }
    closedir($handle);
}
?>

Answer 1

请查看下面的代码段。下面的脚本将找到文件夹中的所有zip文件并将其提取到动态创建的文件夹中。

<?php
//Zip file path`
$path = $_SERVER['DOCUMENT_ROOT'].'/m/';

foreach (glob($path."*.zip") as $filename) {        
    //Destination folder to save extract zip file
    $dest = $path.basename($filename, ".zip");

    //create folder to extract zip file in it.
    mkdir($dest,"0777");
    //Check wether the zip file exist or not.
    if (file_exists($path.$filename)) {
        //create object of ZipArchive class
        $zip = new ZipArchive;

        //Open zip file`
        $res = $zip->open($path.$filename);

        if ($res === TRUE){
            //extract zip file in destination folder`
            $zip->extractTo($dest);   // extract it to the path 
            //close zip file after extracted.
            $zip->close();
        } 
    }
}
?>

Answer 2

你可以使用glob（）;

<?php
foreach (glob("*.txt") as $filename) {
    echo "$filename size " . filesize($filename) . "\n";
}

?>