我试着编写一个解析JSON的函数。函数的返回值是字典array
。不幸的是,我遇到的问题是作业result = data as! [[String:AnyObject]]
不起作用。 print(data)
返回我的JSON很棒,但print(result)
只给我一个空数组。令人惊讶的是方法print(result)
首先运行,然后运行方法print(data)
。
我试过的代码:
import Foundation
import Alamofire
import SwiftyJSON
func getPlayers() -> Array<Dictionary<String, AnyObject>> {
var result = [[String:AnyObject]]()
Alamofire.request(.GET, "http://example.com/api/v1/players", parameters: ["published": "false"])
.responseJSON { (responseData) -> Void in
if((responseData.result.value) != nil) {
let response = JSON(responseData.result.value!)
if let data = response["data"].arrayObject {
print(data)
result = data as! [[String:AnyObject]]
}
}
}
print(result)
return result
}
答案 0 :(得分:4)
Api以async
(后台)方式调用工作,这就是您需要使用swift closure
而不是返回dictionary
的原因。像这样改变你的代码
func getPlayers(completion: (Array<Dictionary<String, AnyObject>>) -> ())) {
var result = [[String:AnyObject]]()
Alamofire.request(.GET, "http://example.com/api/v1/players", parameters: ["published": "false"])
.responseJSON { (responseData) -> Void in
if((responseData.result.value) != nil) {
let response = JSON(responseData.result.value!)
if let data = response["data"].arrayObject {
print(data)
result = data as! [[String:AnyObject]]
}
}
completion(result)
}
}
并像这样打电话
self.getPlayers() { (result) -> () in
print(result)
}