Question

我正在使用一个警告对话框，显示应用程序开头的菜单，我希望对话框显示2个来自对象的“名称”值，这里是警告对话框的代码：

public void showDialog() {

    EntityType en = new EntityType();
    ArrayList array = ApplicationController.entities;

    final AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle("Pick one");
    builder.setItems(array, new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialog, int which) {
            // I want to write my code here
        }
    });

    builder.show();
}

EntityType是我的对象，其中包含字符串“name”，ApplicationController.entities包含数组

Answer 1

尝试以下代码..它适用于我...... :)

AlertDialog.Builder builderSingle = new AlertDialog.Builder(MainActivity.this);
    builderSingle.setIcon(R.drawable.green_tick_add);
    builderSingle.setTitle("Choose..");

    final ArrayAdapter<String> arrayAdapter = new ArrayAdapter<String>(MainActivity.this, android.R.layout.select_dialog_item);
    arrayAdapter.add("Change Photo");
    arrayAdapter.add("Remove Photo");

    builderSingle.setNegativeButton("cancel", new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialog, int which) {
            dialog.dismiss();
        }
    });

    builderSingle.setAdapter(arrayAdapter, new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialog, int which) {
            String strName = arrayAdapter.getItem(which);

        }
    });
    builderSingle.show();

Answer 2

public void showDialog() {

    EntityType en = new EntityType();
    ArrayList array = ApplicationController.entities;

    final AlertDialog.Builder builder = new AlertDialog.Builder(this);
    builder.setTitle("Pick one");
    ArrayList<String> displayValues=new ArrayList<>();
      for (Entity entity : array) {
         displayValues.add(entity.name);
      }

      ArrayAdapter<String> adapter = new ArrayAdapter<String>(getApplicationContext(),android.R.layout.simple_list_item_1,array);
      final AlertDialog.Builder builder = new AlertDialog.Builder(this);
      builder.setTitle("Pick one");
      builder.setSingleChoiceItems(displayValues, 0, new DialogInterface.OnClickListener() {
         @Override
         public void onClick(DialogInterface dialog, int which) {
            Entity selectedItem = array[which];
         }
      });    


    builder.show();
}

Answer 3

ArrayAdapter<String> adapt = new ArrayAdapter<String>(this, android.R.layout.select_dialog);
adapt.add("your entity name");

然后编辑diaolog代码：

builder.setAdapter(adapt, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int item) {
            //write code here
        }
    });

Answer 4

您必须创建一个包含EntityType名称并将其添加到其中的ArrayAdapter：

ArrayAdapter<String> adapt = new ArrayAdapter<String>(this, android.R.layout.select_dialog_singlechoice);
adapt.add("your entity name");

然后在对话框上：

builder.setAdapter(adapt, new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int item) {
            //Your code here
        }
    });

希望有所帮助

在AlertDialog中显示列表

4 个答案: