Question

我的代码计算文件中字母的频率。我的代码：

void incCount (int i, vector<CCount> &chars)
{
    int n;
    n = chars[i].i;
    n++;
    chars[i].i = n;
}

void procWord(string word, vector<CCount> &chars)
{
    for (int i=0; i<word.length(); i++)
    {
        bool found = false;
        char a = word[i];
        for (int j=0; j<chars.size(); j++)
        {
            if (a == chars[j].c)
            {
                bool found = true;
                incCount(j, chars);
            }
        }
        if (found == false)
        {
            CCount c; //CCount is a class with a char and int data type.
            c.c = a;
            c.i = 1;
            chars.push_back(c);
        }
    }
}

int main ()
{
    vector<CCount> chars;
    string word;
    //opening file code here

    while (fin >> word) {
        procWord(word, chars);
    }    
    return 0;
}


class CCount
{
    public:
        char c;
        int i;
};

代码确实累积了字母数，但是当我打印矢量元素时，我得到this。我使用＆＃34;这是一个测试数据＆＃34;作为文件中的测试输入

Answer 1

您再次定义found。请参阅注释行。

您正在定义具有相同名称的变量，并且首选大多数局部变量。

    bool found = false; 

    char a = word[i];
    for (int j=0; j<chars.size(); j++)
    {
        if (a == chars[j].c)
        {
            bool found = true; //this is wrong, just make it found = true;
            incCount(j, chars);
        }
    }

c ++为什么我的代码在向量中创建了额外的元素？

1 个答案: