Question

这个问题让我抓狂。我正在实施APNS。我已经谷歌并遵循了几个教程。我实现了服务器它似乎工作找到这里是代码：

<?php

$deviceToken = 'XXXX';
// Passphrase for the private key (ck.pem file)
// $pass = '';
// Get the parameters from http get or from command line
$message = $_GET['message'] or $message = $argv[1] or $message = 'Message received from javacom';
$badge = (int)$_GET['badge'] or $badge = (int)$argv[2];
$sound = $_GET['sound'] or $sound = $argv[3];

// Construct the notification payload
$body = array();
$body['aps'] = array('alert' => $message);
if ($badge)
    $body['aps']['badge'] = $badge;

if ($sound)
    $body['aps']['sound'] = $sound;

/* End of Configurable Items */

$ctx = stream_context_create();
stream_context_set_option($ctx, 'ssl', 'local_cert', 'ck.pem');
// assume the private key passphase was removed.
//stream_context_set_option($ctx, 'ssl', 'passphrase', $pass);
$fp = stream_socket_client('ssl://gateway.sandbox.push.apple.com:2195', $err, $errstr, 60, STREAM_CLIENT_CONNECT, $ctx); // for production change the server to ssl://gateway.push.apple.com:219
if (!$fp) {
    print "Failed to connect $err $errstr\n";
    return;
} else {
    print "Connection OK\n";
}

$payload = json_encode($body);
$msg = chr(0) . pack("n",32) . pack('H*', str_replace(' ', '', $deviceToken)) . pack("n",strlen($payload)) . $payload;
print "sending message :" . $payload . "\n";
fwrite($fp, $msg);
fclose($fp);

?>

似乎工作正常。我没有得到任何错误。但是我的设备上没有任何推送通知。我不知道错误在哪里。我还实现了反馈脚本。没有错误，也没有输出。我的应用程序也准备好了。提前谢谢。

Answer 1

Apple 发布了一份名为"Troubleshooting Push Notifications"的技术说明。它有发送和接收的提示。也许有些东西可以提供帮助。

Apple推送通知服务 - 设备上没有通知

1 个答案: