如何在sed -ne 's/.*\<\(2016[0-9]\{6\}\)\>.*Serial Number.*/\1/p' filename
Gallery Pro
将mysql
插件表转换为wordpress
?
我需要查找Gallery Pro
插件查询以通过Rest API在App上显示图库图像
在管理员面板中,我使用短代码[WG id=1606]
将新图像添加到图库中
它将行放入wp_posts
表
当我从PC添加图像时,使用post_parent = '1606'
但是当我在服务器上添加图像时,它不会向wp_posts
表添加任何行
答案 0 :(得分:0)
我找到了解决方案:
$lksg_Id = '1606';
$TotalImg = get_post_meta( $lksg_Id, 'lksg_total_images_count', true );
$lksg_Gallery_Settings = "lksg_Gallery_Settings_".$lksg_Id;
$lksg_AllPhotosDetails = unserialize(base64_decode(get_post_meta( $lksg_Id, 'lksg_all_photos_details', true)));
// echo 'All Photos Details : <br /> ' . var_dump($lksg_AllPhotosDetails) . '<br /><br /><br />';
if(count($lksg_Gallery_setting)) {
$lk_gallery_title = $lksg_Gallery_setting['lk_gallery_title'];
$lk_show_image_label = $lksg_Gallery_setting['lk_show_image_label'];
$lk_Gallery_Layout = $lksg_Gallery_setting['lk_Gallery_Layout'];
$wgp_Color = $lksg_Gallery_setting['wgp_Color'];
$lk_label_Color = $lksg_Gallery_setting['lk_label_Color'];
$lk_desc_font_Color = $lksg_Gallery_setting['lk_desc_font_Color'];
$lk_btn_Color = $lksg_Gallery_setting['lk_btn_Color'];
$lk_btn_font_Color = $lksg_Gallery_setting['lk_btn_font_Color'];
$lk_font_style = $lksg_Gallery_setting['lk_font_style'];
$lk_Custom_CSS = $lksg_Gallery_setting['lk_Custom_CSS'];
$lk_show_img_desc = $lksg_Gallery_setting['lk_show_img_desc'];
$lk_Light_Box = $lksg_Gallery_setting['lk_Light_Box'];
$lk_open_link = $lksg_Gallery_setting['lk_open_link'];
$lk_button_title = $lksg_Gallery_setting['lk_button_title'];
}
// echo 'Gallery setting : ' . var_dump($lksg_Gallery_setting) . '<br /><br /><br />';
// echo 'Total Img : ' . var_dump($TotalImg) . '<br /><br /><br />';
$results = array();
if($TotalImg) {
foreach($lksg_AllPhotosDetails as $data) {
// echo 'data : <br /> ' . var_dump($data) . '<br /><br /><br />';
$item = new stdclass();
// $item->id = $data->ID;
$item->title = $data['lksg_image_label'];
$item->content = $data['img_desc'];
$item->image = $data['lksg_image_url'];
$item->tbn = $data['lksg_img_medium'];
$results[] = $item;
}
}
// Finally Return Array As Json String