Question

我有一个字符串，其中包含字段占位符。我需要通过这些占位符拆分字符串，并将字符串和占位符返回到单个数组中。

例如，如果我有字符串：

Ohio is one of the original [s] in the northwest territory.  [s] and [s] were also part of the northwest territory.  Which states are missing [a]?

我希望看到它分成一个数组：

[0] => Ohio is one of the original
[1] => [s]
[2] => in the northwest territory.
[3] => [s]
[4] => and
[5] => [s]
[6] => were also part of the northwest territory.  Which states are missing 
[7] => [a]
[8] => ?

为了满足那些假设我们从未阅读过手册的人，这里有一些我尝试过的代码......我只是无法获得上面列出的格式的数组。我最接近的是这个，但它仍然比我在阵列的某些部分需要更多的文本。我承认，我从未成为REGEX专家，所以感谢您的帮助。

我匹配[]中包含的任何一个字符，即[a]，[b]，[e]等。

preg_match_all("/(.*?)\[(.)\](.*?)/",$string,$x,PREG_SET_ORDER);
print_r($x);

Answer 1

虽然我原本被rjdown的令人讨厌的答案所冒犯，但我确实重新审视了我的所有例子并找到了一个有效的选项。包括“-1”是最后的诀窍。谢谢rjdown

$results =preg_split("/(\[.\])/i",$string, -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);

结果是：

Array
(
    [0] => Ohio is one of the original 
    [1] => [s]
    [2] =>  in the northwest territory.  
    [3] => [s]
    [4] =>  and 
    [5] => [s]
    [6] =>  were also part of the northwest territory.  Which states are missing 
    [7] => [a]
    [8] => ?
)

使用PHP按标签拆分字符串，并用唯一值替换每个标记

1 个答案: