是否可以在yii2中继承ActiveRecord的模型中上传文件?

时间:2016-07-30 21:35:07

标签: file-upload yii2 yii2-model

我从yii2中的数据库表生成了一个带有Gii的模型。这个模型继承自ActiveRecord。然后我从这个模型创建了一个表单。现在我想用这个表单上传一个文件。 是否可以上传具有相同模型的文件(继承自ActiveRecord)?

如果是,怎么样? 如果不是,我该怎么办?

1 个答案:

答案 0 :(得分:0)

是的,这是可能的,但使用单独的表格是更好的做法。它在文章Uploading files

中的官方文档中有详细描述

创建单独的表单:

namespace app\models;

use yii\base\Model;
use yii\web\UploadedFile;

class UploadForm extends Model
{
    /**
     * @var UploadedFile
     */
    public $imageFile;

    public function rules()
    {
        return [
            [['imageFile'], 'file', 'skipOnEmpty' => false, 'extensions' => 'png, jpg'],
        ];
    }

    public function upload()
    {
        if ($this->validate()) {
            $this->imageFile->saveAs('uploads/' . $this->imageFile->baseName . '.' . $this->imageFile->extension);
            return true;
        } else {
            return false;
        }
    }
}

渲染文件输入:

<?php $form = ActiveForm::begin(['options' => ['enctype' => 'multipart/form-data']]) ?>

    <?= $form->field($model, 'imageFile')->fileInput() ?>

    <button>Submit</button>

<?php ActiveForm::end() ?>

自定义控制器以处理文件上传:

namespace app\controllers;

use Yii;
use yii\web\Controller;
use app\models\UploadForm;
use yii\web\UploadedFile;

class SiteController extends Controller
{
    public function actionUpload()
    {
        $model = new UploadForm();

        if (Yii::$app->request->isPost) {
            $model->imageFile = UploadedFile::getInstance($model, 'imageFile');
            if ($model->upload()) {
                // file is uploaded successfully
                return;
            }
        }

        return $this->render('upload', ['model' => $model]);
    }
}

本文还介绍了上载多个文件。

另见this related question

如果要将其与ActiveRecord一起使用并将文件路径另存为模型属性,则可以添加模型创建并保存在upload()表单方法中。使用表单的另一个好例子是高级模板中的SignupForm

<?php

namespace frontend\models;
use yii\base\Model;
use common\models\User;

/**
 * Signup form
 */
class SignupForm extends Model
{
    public $username;
    public $email;
    public $password;


    /**
     * @inheritdoc
     */
    public function rules()
    {
        return [
            ['username', 'trim'],
            ['username', 'required'],
            ['username', 'unique', 'targetClass' => '\common\models\User', 'message' => 'This username has already been taken.'],
            ['username', 'string', 'min' => 2, 'max' => 255],
            ['email', 'trim'],
            ['email', 'required'],
            ['email', 'email'],
            ['email', 'string', 'max' => 255],
            ['email', 'unique', 'targetClass' => '\common\models\User', 'message' => 'This email address has already been taken.'],
            ['password', 'required'],
            ['password', 'string', 'min' => 6],
        ];
    }

    /**
     * Signs user up.
     *
     * @return User|null the saved model or null if saving fails
     */
    public function signup()
    {
        if (!$this->validate()) {
            return null;
        }

        $user = new User();
        $user->username = $this->username;
        $user->email = $this->email;
        $user->setPassword($this->password);
        $user->generateAuthKey();

        return $user->save() ? $user : null;
    }
}

正如您所看到的,模型的验证和创建被分离为单独的形式,这是更好的实践,而不是直接在模型中处理它(尤其是文件上传)。但是出于简单的目的,仅使用模型也是可以接受的。