说明:我试图建立一个接受答案的系统,有三种情况:
这是我的代码:
$("body").on('click', '.fa-check', function(e) {
// send a request by ajax and if it is successful then
if( this.attr('color') == '#44b449' ){ // undo
this.css({"color":"#aaa"}); // set gry color to marked icon
} else { // switchin or marking a new one
$('.fa-check').css({"color":"#aaa"}); // set gray color to all icons
this.css({"color":"#44b449"}); // set green color to marked icon
}
});

.fa-check{
color:#aaa;
cursor: pointer;
}
.fa-check:hover{
color: #999;
}

<script src="https://use.fontawesome.com/9e9ad91d21.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p>answer1</p>
<i class="fa fa-check" aria-hidden="true"></i>
<hr>
<p>answer2</p>
<i class="fa fa-check" aria-hidden="true" style="color: #44b449;"></i>
<hr>
<p>answer3</p>
<i class="fa fa-check" aria-hidden="true"></i>
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但是当你看到我的代码不起作用时。我该如何解决?
注意:我的整个问题都是关于着色。
答案 0 :(得分:3)
首先,当你引用dQuerylement而不是jQuery对象时,你在this
上调用jQuery方法时,你的代码会抛出错误。
要解决您的问题,您可以使用类而不是应用内联CSS样式来简化逻辑。这使您只需在单击.fa-check
元素时切换类。试试这个:
$("body").on('click', '.fa-check', function(e) {
// send a request by ajax and if it is successful then
$('.fa-check').not(this).removeClass('checked');
$(this).toggleClass('checked');
});
.fa-check {
color: #aaa;
cursor: pointer;
}
.fa-check.checked {
color: #44b449;
}
<script src="https://use.fontawesome.com/9e9ad91d21.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p>answer1</p>
<i class="fa fa-check" aria-hidden="true"></i>
<hr>
<p>answer2</p>
<i class="fa fa-check checked" aria-hidden="true"></i>
<hr>
<p>answer3</p>
<i class="fa fa-check" aria-hidden="true"></i>
答案 1 :(得分:0)
使用此方法
function click_div(div) {
$("#main_div div .fa-check").css("color"," #aaa");
$("#"+div+" .fa-check").css("color"," #44b449");
}
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#div_1,#div_2,#div_3
{
width:100%;
height:100px;
}
.fa-check{
color:#aaa;
cursor: pointer;
}
.fa-check:hover{
color: #999;
}
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<html>
<head>
<script src="https://use.fontawesome.com/9e9ad91d21.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
</head>
<div id="main_div">
<div id="div1" onclick="click_div('div1')">
<p>answer1</p>
<i class="fa fa-check" aria-hidden="true"></i>
</div>
<hr>
<div id="div2" onclick="click_div('div2')">
<p>answer2</p>
<i class="fa fa-check" aria-hidden="true" style="color: #44b449;"></i>
</div>
<hr>
<div id="div3" onclick="click_div('div3')">
<p>answer3</p>
<i class="fa fa-check" aria-hidden="true"></i>
</div>
</div>
</html>
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