我有3张桌子
t1 (select these records)
-------------
id
offer_id
business_id
t2 (offer details)
-------------
id
offer_details
business_id
t3 (business details)
-------------
id
business_name
我需要从t1中选择所有记录并从t2和t3添加信息。似乎基本但我似乎无法做到正确 - 必须是热量。
SELECT t2.offer_details, t3.business_name
FROM t2
LEFT JOIN t1 ON (t1.offer_id = t2.id)
LEFT JOIN t3 ON (t1.business_id = t3.id)
答案 0 :(得分:1)
这个怎么样
Select t2.offer_details, t3.business_name
From t1
Left Join t2 ON (t1.offer_id = t2.id)
Left Join t3 ON (t1.business_id = t3.id)
答案 1 :(得分:1)
应该是
SELECT t2.offer_details, t3.business_name
FROM t1
LEFT JOIN t1 ON (t1.offer_id = t2.id)
LEFT JOIN t3 ON (t1.business_id = t3.id)
您的潜在客户表是t1,联接应该基于此表
答案 2 :(得分:1)
如果您想要来自t1的所有记录,请在您选择的部分添加t1.*
。假设t1中的所有ID都存在于其他2个表中
SELECT
t1.*, t2.offer_details, t3.business_name
FROM
t1
JOIN t2 ON t2.id = t1.offer_id
JOIN t3 ON t3.id = t1.business_id
如果在t2或t3中缺少t1中的ID,则修改为LEFT JOIN
。