我有一个视图,在此视图中有3个按钮:
showListOne()
showListTwo()
showListThree()
当点击每个按钮时,我想在同一视图但不同时呈现不同的列表(一次只显示一个列表,如标签行为)。
所以我想用枚举来做,这就是:
export enum CurrentListView {People,Cars,Places}
@Component({
selector: 'my-app',
styles: [require('./my-app.css')],
directives: [DND_DIRECTIVES],
providers: [DND_PROVIDERS],
template: require('./my-app.component.html')
})
@Injectable()
export class AppCmp implements OnInit {
listOfPeople: Person[];
listOfCars: Car[];
listOfPlaces: Place[];
currentListView: CurrentListView;
constructor(private _MyService: MyService) {
};
public showListOfPeopleData(): void {
this.currentListView = CurrentListView.People;
}
public showListOfCarsData(): void {
this.currentListView = CurrentListView.Cars;
}
public showListOfPlacesData(): void {
this.currentListView = CurrentListView.Places;
}
ngOnInit() {
this._MyService.getListOfPeopleData().subscribe(res => {
this.listOfPeople = res;
});
this._MyService.getListOfCarsData().subscribe(res => {
this.listOfCars = res;
});
this._MyService.getListOfPlacesData().subscribe(res => {
this.listOfPlaces = res;
});
}
}
现在,如何使用ng-if询问currentListView
的状态?这是我的观点(如果有我尝试的东西并且它有效的话):
<div *ngIf="currentListView == CurrentListView.People">
<div dnd-sortable-container [dropZones]="['zone-one']" [sortableData]="listOfPeople">
<div class="list-bg" *ngFor="#person of listOfPeople; #i = index" dnd-sortable [sortableIndex]="i">
ID: {{person.id}} <p></p> Age: {{person.age}}
</div>
</div>
</div>
<div *ngIf="currentListView == CurrentListView.Cars">
<div dnd-sortable-container [dropZones]="['zone-one']" [sortableData]="listOfCars">
<div class="list-bg" *ngFor="#car of listOfCars; #i = index" dnd-sortable [sortableIndex]="i">
ID: {{car.id}} <p></p> Color: {{car.color}}
</div>
</div>
</div>
<div *ngIf="currentListView == CurrentListView.Places">
<div dnd-sortable-container [dropZones]="['zone-one']" [sortableData]="listOfPlaces">
<div class="list-bg" *ngFor="#place of listOfPlaces; #i = index" dnd-sortable [sortableIndex]="i">
City: {{place.city}} <p></p> Capacity: {{place.capacity}}
</div>
</div>
</div>
我的打字稿或HTML可以更有效吗?我希望看到一个更通用的方法来建议,而不是重复...
感谢分配!
答案 0 :(得分:0)
我认为你不能比较阵列(不管它是不好的表现), 我建议您可以存储&#34;要显示的列表&#34;在一些字符串变量中 像这样的东西:
currentListView:string = 'Bikes';
就像这个plunkr
一样