如何在用户注册期间在firebase中的实时数据库中存储数据?

时间:2016-07-30 17:58:44

标签: android firebase firebase-realtime-database firebase-authentication

我正在制作具有用户个人资料的类似社交媒体的应用。我想在使用他们的uid注册时保存他们的个人资料数据。虽然注册成功,但配置文件未保存在firebase数据库中。我还检查了规则,并为经过身份验证的用户设置了读写功能。

这是我的代码:

public class RegisterActivity extends AppCompatActivity implements View.OnClickListener {

private Button btn_reg;
private EditText etName, etEmail, etPassword, etCPassword, etMobile, etSchoolCompany, etLocation;
private ProgressDialog progressDialog;
private FirebaseAuth firebaseAuth;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    Firebase.setAndroidContext(this);

    firebaseAuth = FirebaseAuth.getInstance();

    progressDialog = new ProgressDialog(this);

    btn_reg = (Button)findViewById(R.id.btnRegister);
    etName = (EditText)findViewById(R.id.etName);
    etEmail = (EditText)findViewById(R.id.etEmail);
    etPassword = (EditText)findViewById(R.id.etPassword);
    etCPassword = (EditText)findViewById(R.id.etCPassword);
    etMobile = (EditText)findViewById(R.id.etMobile);
    etSchoolCompany = (EditText)findViewById(R.id.etSchoolCompany);
    etLocation = (EditText)findViewById(R.id.etLocation);

    btn_reg.setOnClickListener(this);
}

@Override
public void onClick (View view){
    if(view == btn_reg){
        registerUser();
    }
}

private void registerUser(){
    String name = etName.getText().toString();
    String mobile = etMobile.getText().toString();
    String SchoolCompany = etSchoolCompany.getText().toString();
    String location = etLocation.getText().toString();
    final String email = etEmail.getText().toString().trim();
    final String password = etPassword.getText().toString().trim();
    String cpassword = etCPassword.getText().toString().trim();

    progressDialog.setMessage("Registering..");
    progressDialog.show();

    //REGISTERING USER
    firebaseAuth.createUserWithEmailAndPassword(email, password)
            .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) {
                    if(task.isSuccessful()){

                        //THIS IS FOR STORING AUTHENTICATED USER'S DATA
                        final Firebase ref = new Firebase("https://myfirebase.firebaseio.com");
                        ref.authWithPassword(email, password, new Firebase.AuthResultHandler(){
                            @Override
                            public void onAuthenticated(AuthData authData){
                                // Authentication just completed successfully :)
                                Map<String, String> map = new HashMap<String, String>();
                                map.put("provider", authData.getProvider());
                                if(authData.getProviderData().containsKey("displayName")) {
                                    map.put("displayName", authData.getProviderData().get("displayName").toString());
                                }
                                ref.child("users").child(authData.getUid()).setValue(map);
                            }
                            @Override
                            public void onAuthenticationError(FirebaseError error) {
                //ERRORS TODO
                            }
                        });
                        progressDialog.hide();
                        Toast.makeText(RegisterActivity.this, "Registered Successfully", Toast.LENGTH_SHORT).show();
                    }else{
                        Toast.makeText(RegisterActivity.this, "Registration failed, please try again", Toast.LENGTH_SHORT).show();
                    }
                }

            });
}


}

3 个答案:

答案 0 :(得分:4)

来自createUserWithEmailAndPassword method reference

  

尝试使用给定的电子邮件地址和密码创建新的用户帐户。 如果成功,它还会将用户签入应用程序。

这意味着您无需在注册过程完成后再次对用户进行身份验证。

要确保任务完成且firebaseUser不为空,最好将AuthStateListener添加到FirebaseAuth,而不是在onComplete方法中保存数据,代码在the official guide

然后,如果用户通过身份验证,您可以保存数据。

public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
    FirebaseUser user = firebaseAuth.getCurrentUser();
    if (user != null) {
        DatabaseReference ref = FirebaseDatabase.getInstance().getReference();
        Map<String, String> map = new HashMap<>();
        map.put("provider", user.getProviders().get(0));
        if(user.getProviderData().containsKey("displayName")) {
            map.put("displayName", user.getProviderData().get("displayName").toString());
        }
        ref.child("users").child(user.getUid()).setValue(map);
    } 
}

答案 1 :(得分:2)

假设您要在数据库中添加用户名,请编写

String name = etName.getText().toString().trim();

然后只需创建DatabaseReference类的对象,例如:

 DatabaseReference myRootRef = FirebaseDatabase.getInstance().getReference();

 DatabaseReference userNameRef =  myRootRef.child("User Name");

 userNameRef.setValue(name);

// to add email
String email = etEmail.getText().toString().trim();
DatabaseReference userEmail = myRootRef.child("Email ");
userEmail.setValue(email);

以同样的方式,你可以做其余的事情

这会将数据存储为JSON树,其中根为myRootRef,其子项为userNameRef

答案 2 :(得分:1)

对于遇到类似问题的其他人,Firebase中未保留数据的常见原因是Realtime Database|Rules中的子名称与您的java代码中的名称不匹配:

enter image description here

Java代码:

enter image description here

再次,您应该致电:

ref.child("users").child(firebaseUser.getUid()).setValue(<YOUR_POJO_OBJECT>);

而不是

 ref.child("users").child(authData.getUid()).setValue(map);