android模拟位置不与locationservices.fusedlocationapi一起使用

时间:2016-07-30 11:57:10

标签: android location google-api-client fusedlocationproviderapi

从谷歌商店下载并使用“假Gps”后,我想创建一个用于教育目的。

我使用GoogleApiClient FusedLocationAPI获取当前位置和创建模拟位置。我能够获取当前位置,但无法模拟位置。

public class GoogleApiClientGeoLocation implements GoogleApiClient.ConnectionCallbacks, GoogleApiClient.OnConnectionFailedListener, LocationListener {
    private GoogleApiClient googleApiClient;

    public GoogleApiClientGeoLocation(Context activity) {
        googleApiClient = new GoogleApiClient.Builder(activity, this, this).addApi(LocationServices.API).build();
        ....
    }

    public void connect() {
        if (googleApiClient != null) {
           googleApiClient.connect();
        }
    }

    public void disconnect() {
        googleApiClient.disconnect();
    }

    @Override
    public void onConnected(@Nullable Bundle bundle) {
        LocationServices.FusedLocationApi.requestLocationUpdates(googleApiClient, locationRequest, this);
    }

    @Override
    public void onLocationChanged(Location location) {
        Log.e("TAG","Location changed"+location.getLatitude() + ", "+ location.getLongitude());
    }

    private static final String PROVIDER = LocationManager.NETWORK_PROVIDER;//"flp";
    private static final double LAT = 37.377166;
    private static final double LNG = -122.086966;
    private static final float ACCURACY = 3.0f;

    public Location createLocation(double lat, double lng, float accuracy) { //<-for testing purposes using a static lat,long
        // Create a new Location
        Location newLocation = new Location(PROVIDER);
        newLocation.setLatitude(LAT);
        newLocation.setLongitude(LNG);
        newLocation.setAltitude(1000);
        newLocation.setElapsedRealtimeNanos(System.nanoTime());
        newLocation.setTime(System.currentTimeMillis());
        newLocation.setAccuracy(500);
        return newLocation;
    }

    public void startMock() {
        LocationServices.FusedLocationApi.setMockMode(googleApiClient, true);
    }
    public void stopMock() {
        LocationServices.FusedLocationApi.setMockMode(googleApiClient, false);
    }
    public void domock() {
        Location testLocation = createLocation(LAT, LNG, ACCURACY);
        if (ContextCompat.checkSelfPermission(_context, android.Manifest.permission.ACCESS_FINE_LOCATION)
            == PackageManager.PERMISSION_GRANTED) {

            LocationServices.FusedLocationApi.setMockLocation(googleApiClient, testLocation);
            Log.e("TAG","Location Mocked");
        }else{
            Log.e("TAG","Can not Mock location");
        }
    }
}

我有一个GoogleApiClientGeoLocation类来处理所有函数。 流程是初始化 - &gt; connect-&gt; startmock-&gt; mock-&gt; stopmock-&gt; disconnect

如果我执行connect(),则locationchange()为我提供当前位置,但是当我使用startmock()和domock()时,locationchange()暂停并且不返回任何内容,并且当我stopmock()时,locationchange()开始给我当前的位置位置。

我收到一条日志消息,上面写着'location mocked'。

我的'提供者'错了吗?

我希望能够创建一个模拟位置,并能够访问谷歌地图并看到它指向模拟位置。

1 个答案:

答案 0 :(得分:1)

看起来FusedLocationProvider与系统时钟的时钟不同。即elapsedRealTimeNanosSystem.nanoTime不同。因此,您使用系统时钟设置的时间将关闭,我假设新的位置被视为过时且无效。

要获得有效的elapsedRealTimeNanos,每次创建模拟位置时,我都会向System.nanoTime()添加偏移量。我第一次连接到googleApiClient时计算出偏移量:

Location current = LocationServices.FusedLocationApi.getLastLocation(googleApiClient);
nanoOffset = current.getElapsedRealtimeNanos() - System.nanoTime();

然后,我创建的完整模拟位置如下:

Location location = new Location("flp");  // indicates mock 
locationlocation.setLatitude(latLon.getLat());
location.setLongitude(latLon.getLon());
location.setTime(System.currentTimeMillis());
location.setAccuracy(6f);
location.setElapsedRealtimeNanos(System.nanoTime() + nanoOffset);